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galina1969 [7]
3 years ago
13

A study of an association between which ear is used for cell phone calls and whether the subject is​ left-handed or​ right-hande

d began with a survey​ e-mailed to 5000 people belonging to an otology online​ group, and 717 surveys were returned.​ (Otology relates to the ear and​ hearing.) What percentage of the 5000 surveys were​ returned? Does that response rate appear to be​ low? In​ general, what is a problem with a very low response​ rate? Of the 5000​ surveys, nothing​% were returned. This response rate ▼ appears does not appear to be low.
Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

Of the 5000​ surveys, 14​% were returned. This response rate APPEARS to be low.

Step-by-step explanation:

Given:

Total sample collected = 5000

Survey returned = 700

i) What percentage of the 5000 surveys were​ returned?

To find percentage returned, we have:

= \frac{700}{5000} * 100 = 14 percent

Percentage returned = 14%

ii) Does that response rate appear to be​ low?

Yes, the response is significantly low as only 14% is returned out of expected 100%

iii) In​ general, what is a problem with a very low response​ rate?

The problem with in low response rate in general is that it causes the result to be biased as biased samples of those interested in a particular aspect may have been gotten.

Therefore, of the 5000​ surveys, 14​% were returned. This response rate APPEARS to be low.

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Lyrx [107]

Answer:

24 pieces of bread

9 eggs

3 cups of milk

4.5 teaspoon of cinnamon

7 0
3 years ago
An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem
Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

\dfrac{w-1}{b+w-1}

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of \frac{w}{b+w} of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability \frac{b}{b+w} of picking a black ball with both picks.

This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

Of picking two balls of the same colour.

<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y

And this is our case, because in our case we have

  1. x=b^2+w^2
  2. y=b^2+w^2+2bw so, y has an extra piece and it is larger
  3. k=b+w which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

4 0
3 years ago
Next number in the sequence 1 4 9 16 25
Anarel [89]

The next number in the sequence is 36.

Starting from 1, the number increases by 3, 1 + 3 = 4. But the next number, the number it's being increased by increases by 2. 3 + 2 = 5, 4 + 5 = 9. And again, 5 + 2 = 7, 7 + 9 = 16. And again. 7 + 2 = 9, 16 + 9 = 25. Therefore, it is increased to + 11, and the next number is 36.

I hope this helped, and you have a great day!

3 0
3 years ago
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yulyashka [42]

Answer:

A) 40 feet.

B) 7 inches.

Step-by-step explanation:

A) To acquire 8 inches, multiply the corresponding scale factor by 8:

1 inch equals 5 feet; 8 inches equals 40 feet

The genuine house stands 40 feet tall.

B) You can write the percentage if you want...

dwg / (35 feet) = 1 in / (5 ft)

When you multiply by 35 feet, you get...

7 in dwg = (1 in)(35 ft)/(5 ft)

In the scale drawing, the home measures <em>7 inches in length</em>.

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Solve the following computation: 8.29 – 3.112
Ymorist [56]

Answer:

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Step-by-step explanation:

Cancel the 9 for an 8

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