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babunello [35]
3 years ago
7

A science teacher showed an image of a carpenter bee on a wall. The image is 10 times as large as the actual bee.

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
PLease state ure question if the bee is on a wall.Whaat size is the bee?
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Evaluate 3x - 4y + 11 for x = -2 and y = -1
katrin [286]

Answer:

9

Step-by-step explanation:

Plug in -2 for x, and -1 for y, and solve:

3x - 4y + 11

3(-2) - 4(-1) + 11

Remember to follow PEMDAS. First, multiply. Remember, that when you multiply:

2 positive signs will result in a positive answer.

1 positive & 1 negative will result in a negative answer.

2 negative will result in a positive answer.

3 * -2 = -6

-4 * -1 = 4

-6 + 4 + 11 = 9

9 is your answer.

~

7 0
3 years ago
Read 2 more answers
What is the ratio of the wavelengths of these two notes? a. 5 to 4 b. 3 to 2 c. 6 to 5 d. 2 to 1
Phoenix [80]

The ratio of the wavelengths of the two notes is 2:1 option fourth 2 to 1 is correct.

<h3>What is wavelength?</h3>

The wavelength is the distance between two successive troughs or crests. The highest point on the wave is the crest, while the lowest point is the trough.

We have two notes

Number of cycle for blue = 8

Number of cycle for red = 4

Ratio = 8:4 = 2:1

Or

2 to 1

Thus, the ratio of the wavelengths of the two notes is 2:1 option fourth 2 to 1 is correct.

Learn more about the wavelength here:

brainly.com/question/7143261

#SPJ1

4 0
2 years ago
Find the mode of the set data: 49, 41, 46, 28, 33, 47, 29, 27, 47, 52, 32.
Rashid [163]
47 is the answer ........
4 0
3 years ago
Y + 43 &gt; 30 then m could be
MArishka [77]

Answer:

M could be 15!

Step-by-step explanation:

As long as Y is greater than M, it should be Y + 43 > 30 + M.

Hope this helps.

4 0
2 years ago
Simplify the expression.<br><br> [(11 - 4)^3]^2 ÷ (4 + 3)^5
slavikrds [6]

Answer:

<h2>7</h2><h2>:)</h2><h2 />

Step-by-step explanation:

\left[\left(11\:-\:4\right)^3\right]^2\:\div \left(4\:+\:3\right)^5\\\\\frac{\left(\left(11-4\right)^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Subtract\:the\:numbers:}\:11-4=7\\\\=\frac{\left(7^3\right)^2}{\left(4+3\right)^5}\\\\\mathrm{Add\:the\:numbers:}\:4+3=7\\\\=\frac{\left(7^3\right)^2}{7^5}\\\\\left(7^3\right)^2=7^6\\\\=\frac{7^6}{7^5}\\\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\\\frac{7^6}{7^5}=7^{6-5}\\\\\mathrm{Subtract\:the\:numbers:}\:6-5=1\\\\=7

4 0
3 years ago
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