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mel-nik [20]
3 years ago
8

Counting Principles

Mathematics
1 answer:
REY [17]3 years ago
6 0
It would be all the numbers times eachother 3x12x10=360
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Find the value of x.
arlik [135]

Answer:

it stands for multiplication or if it on top of something it is division was that helpful or not commet down below

Step-by-step explanation:

8 0
3 years ago
5,30,180,1080 what is the common difference
KIM [24]
The given sequence is not arithmetic so, it doesn't has common difference.
8 0
3 years ago
Hi! ❤️ , im looking for some help here. ill give brainliest if able to.
Alexeev081 [22]

Answer:

A. 2^11

Step-by-step explanation:

(They are basically asking what's 2^4 × 2^7, but with more words.)

I usually do each exponent individually:

2^4 is the same as 2 × 2 × 2 × 2 = 16 (or you could have read the text to figure that out)

2^7 is the same as 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128

Then just multiply 128 and 16 to get 2,048, and see which option also gives you 2,048.

BUT, you can also:

(Combine the exponents together to get your answer. Just remember that if it's multiplication you add them, and if it's division you subtract them.)

2^4 × 2^7

4 + 7 = 11

2^11 (This equals 2,048 btw. You don't even have to check all the options to get the answer).

Hope this helps friend :)

The last part I learned from another user, while answering one of your other questions. I personally find this mind blowing, lol.

4 0
2 years ago
HELP ILL GIVE BRAINLIEST
SVETLANKA909090 [29]

Answer:

\huge\boxed{\bf\:c = \frac{11}{4}}

Step-by-step explanation:

4c + 2c = 4c + \frac{11}{2}

Cancel 4c on both the sides of the equation.

2c = \frac{11}{2}

Bring the 2 in the denominator of 11/2 to the left hand side of the equation.

2*2c = 11\\4c = 11

Bring 4 to the right hand side if the equation.

\boxed{\bf\:c = \frac{11}{4}}

\rule{150pt}{2pt}

4 0
2 years ago
What is the yintercept in the equation y=4x-3?
sergejj [24]

Answer:

-3

Step-by-step explanation:

The main formula for slope intercept form is y=mx+b

m=slope

b=y-intercept

3 0
3 years ago
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