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saul85 [17]
3 years ago
5

Consider the function f(x)= x(x-4)

Mathematics
2 answers:
Alexeev081 [22]3 years ago
6 0
(2-c,y) is the answer for the problem.
PSYCHO15rus [73]3 years ago
4 0

Answer:

option (1) is correct.

point (c-2, y) lies on the graph of  f(x)=x(x-4).

Step-by-step explanation:

Given function f(x)=x(x-4) also point (2+ c,y) is on the graph of f(x) ,

We have to find out of given point which point will also be on the graph of f(x).

Consider  the given function f(x)=x(x-4)

f(x)=x(x-4) can be rewritten  f(x)=x^2-4x

Now we substitute the given point (2+ c, y) in the function given ,

we have,

f(x)=y=x(x-4)

put for x as 2+c , we have,

\Rightarrow y=(2+c)(2+c-4)

Solve, we get

\Rightarrow y=(2+c)(c-2)

Thus, both point (2+c, y) and (c-2, y) lies on the graph of  f(x)=x(x-4)

Thus, option (1) is correct.

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Answer:

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Step-by-step explanation:

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34.53 / 5

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Hope this helps!

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2 years ago
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-3x2 (xy+2x2) + 7x4 -3x3(5y + x)??
allochka39001 [22]

Answer:

−2x4−18x3y

Step-by-step explanation:

Let's simplify step-by-step.

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Distribute:

=(−3x2)(xy)+(−3x2)(2x2)+7x4+−3x4+−15x3y

=−3x3y+−6x4+7x4+−3x4+−15x3y

Combine Like Terms:

=−3x3y+−6x4+7x4+−3x4+−15x3y

=(−6x4+7x4+−3x4)+(−3x3y+−15x3y)

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4 0
3 years ago
How do you rewrite 7bx+7by
san4es73 [151]
Set 7b as a common factor and put it outside the parentheses:
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Check:
7b(x+y)
Distribute the 7b
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3 years ago
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