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Step2247 [10]
1 year ago
5

Cameron is a member of a national gardening club. she asked 200 of her fellow members whether they use compost to fertilize thei

r plants, and 45% responded favorably. what is the 90% confidence interval for the true proportion of club members who use compost?
Mathematics
2 answers:
lara31 [8.8K]1 year ago
5 0

Answer:

The answers are 0.45 and 0.06

Step-by-step explanation:

I took the test!

krok68 [10]1 year ago
4 0

Using the z-distribution, it is found that the 90% confidence interval for the true proportion of club members who use compost is (0.392, 0.508).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The estimate and the sample size are given by:

\pi = 0.45, n = 200

Hence, the bounds of the interval are:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 - 1.645\sqrt{\frac{0.45(0.55)}{200}} = 0.392

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.45 + 1.645\sqrt{\frac{0.45(0.55)}{200}} = 0.508

More can be learned about the z-distribution at  brainly.com/question/25890103

#SPJ4

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