Can someone please simplify the complex fraction?

Mathematics

1 answer:

dmitriy555 [2]3 years ago

8 0

$\bf \cfrac{\qquad \frac{x+3}{4x^2-16}\qquad }{\frac{2x^2+10x+12}{2x-4}}\implies \cfrac{\frac{x+3}{4(x^2-4)}}{\frac{\underline{2}(x^2+5x+6)}{\underline{2}(x-2)}}\implies \cfrac{\frac{x+3}{4(x^2-2^2)}}{\frac{x^2+5x+6}{x-2}}\implies \cfrac{\frac{x+3}{4(x-2)(x+2)}}{\frac{(x+3)(x+2)}{x-2}}$

$\bf \cfrac{\underline{x+3}}{4\underline{(x-2)}(x+2)}\cdot \cfrac{\underline{x-2}}{\underline{(x+3)}(x+2)}\implies \cfrac{1}{4(x+2)}\cdot \cfrac{1}{x+2}
\\\\\\
\cfrac{1}{4(x+2)(x+2)}\implies \cfrac{1}{4(x^2+4x+4)}\implies \cfrac{1}{4x^2+16x+16}$

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M<2 = 34. Find m<4 and explain how you know.

Basile [38]

Answer:

m<4 = 34°

Step-by-step explanation:

m<2 = 34° (given)

m<3 + m<2 = 180° (linear pair)

m<3 + 34° = 180° (substitution)

Subtract 34° from each side

m<3 = 180° - 34°

m<3 = 146°

m<4 + m<3 = 180° (linear pair)

m<4 + 146° = 180° (substitution)

Subtract 146° from each side

m<4 = 180° - 146°

m<4 = 34°

This shows that vertical angles are congruent.

m<2 and m<4 are vertical angles formed when two straight line intersects. They are both of equal measure.

3 0

3 years ago

PLEASE HELP :DDDDDDDDDD

Maslowich

Ok start off by finding the base first and the equation of finding the area of the square is A=bh
A=11 x 11= 121 cm^2

Next find the area of one triangle and the equation is A=1/2bh
A=1/2(11)(10)
A=55 cm^2

Multiply the area of one triangle by 4 since there are four triangles and it should equal to 220 cm^2. You then add this to the base and the final answer should be 341 cm^2.

I hope this helps

6 0

3 years ago

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Write the sentence as an equation, using x as the variable. Then find the solution of the equation from the set of integers bet

Inessa05 [86]

Answer:

The solution of given equation is x = -4

Step-by-step explanation:

We are given the following in the question:

Let x be the variable such that

$x \in (-12,12)$