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AveGali [126]
3 years ago
6

Can someone please simplify the complex fraction?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0
\bf \cfrac{\qquad \frac{x+3}{4x^2-16}\qquad }{\frac{2x^2+10x+12}{2x-4}}\implies \cfrac{\frac{x+3}{4(x^2-4)}}{\frac{\underline{2}(x^2+5x+6)}{\underline{2}(x-2)}}\implies \cfrac{\frac{x+3}{4(x^2-2^2)}}{\frac{x^2+5x+6}{x-2}}\implies \cfrac{\frac{x+3}{4(x-2)(x+2)}}{\frac{(x+3)(x+2)}{x-2}}

\bf \cfrac{\underline{x+3}}{4\underline{(x-2)}(x+2)}\cdot \cfrac{\underline{x-2}}{\underline{(x+3)}(x+2)}\implies \cfrac{1}{4(x+2)}\cdot \cfrac{1}{x+2}
\\\\\\
\cfrac{1}{4(x+2)(x+2)}\implies \cfrac{1}{4(x^2+4x+4)}\implies \cfrac{1}{4x^2+16x+16}
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Hello help please and thanks
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Answer:

48.

Step-by-step explanation:

33 + 15 = 48.

You can check your answer by subtracting 48-15, which gives you 33.

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What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768
Pani-rosa [81]

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To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

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Decimal form = 0.8

Fraction form = 4/5

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Check:

1.5 x 0.8 = 1.2

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Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Ksenya-84 [330]

<u>Part a)</u> Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours  

we know that

x+y \leq20 --------> inequality 1  

6x+10y \geq 75 --------> inequality 2

<u>Part b)</u> Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

x+y \leq20 --------> inequality 1

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 1

6x+10y \geq 75 --------> inequality 2  

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 2

<u>Part c)</u> Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

x+y \leq20 --------> inequality 1

6x+10y \geq 75 --------> inequality 2

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N  3

Let

A(10,10) ------> see the attached figure N  3

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

<u>Prove algebraically </u>

A(10,10)

substitute the value of x and y in the inequalities

<u>inequality 1</u>

10+10 \leq20

20 \leq20 ------> is ok

<u>inequality 2</u>

6*10+10*10 \geq 75

160 \geq 75 -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0
3 years ago
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