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3 years ago

What is the discriminant of the polynomial below? 2x^2+3x-7

Mathematics

1 answer:

Katena32 [7]3 years ago

7 0

Answer:

Option C. $65$

Step-by-step explanation:

we know that

The discriminant of a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$D=b^{2}-4ac$

in this problem we have

$2x^{2} +3x-7$

$a=2\\b=3\\c=-7$

substitute

$D=3^{2}-4(2)*(-7)$

$D=9+56$

$D=65$

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MatroZZZ [7]

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3 years ago

The point (0,10) is called a ____-intercepta?

RUDIKE [14]

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2 years ago

What is the answer to the math problem 6+(-3)

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3 years ago

Read 2 more answers

Perform the indicated operations; reduce the answer to lowest terms.

kow [346]

a. 9/10

explanation:

• the denominators (bottom number) are the same so there is no need to change to a common factor

• because the fractions have common factors, you add the top numbers (3+6) to get 9

• then you put the top number over the 10 (9/10) and it’s simplified as much as possible

b. 3/4

explanation:

• each denominator (bottom term) is a factor of 12 so you have to change each fraction to #/12

• to change 1/3, you multiply the top and bottom numbers by 4 (1x4 & 3x4 = 4/12)

• to change 1/4, you multiply the top and bottom numbers by 3 (1x3 & 4x3 = 3/12)

• to change 1/6, you multiple the top and bottom numbers by 2 (1x2 & 6x2 = 2/12)

• then you add each of the top numbers (4+3+2) and put it over the common denominator (12) to get 9/12

- both 9 & 12 are divisible by 3, so you simply by dividing both by 3 to get 3/4

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explanation:

•the denominators are the same, so you subtract 5-3 without changing the denominator & you get 2/6

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3 years ago

Last year, Susan had 10,000 to invest. She invested some of it in an account that paid 6%

katrin2010 [14]

Answer:

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

Part a) account that paid 6% simple interest per year

in this problem we have

$t=1\ years\\ P=\$x\\r=0.06$

substitute in the formula above

$I1=x(0.06*1)$

$I1=0.06x$

Part b) account that paid 5% simple interest per year

in this problem we have

$t=1\ years\\ P=\$10,000-\$x\\r=0.05$

substitute in the formula above

$I2=(10,000-x)(0.05*1)$

$I2=500-0.05x$

we know that

$I1+I2=\$560$

substitute and solve for x

$0.06x+500-0.05x=560$

$0.01x=560-500$

$0.01x=60$

$x=\$6.000$

therefore

In the account that paid 6% Susan invest $\$6,000$

In the account that paid 5% Susan invest $\$4,000$

6 0

3 years ago