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Alex17521 [72]
3 years ago
9

Which of the following is a Pythagorean triple?

Mathematics
1 answer:
Anastasy [175]3 years ago
4 0
The right answer is D
9^2+40^2=1681=41^2
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Witch quadrilateral has 2 acute angles,2 obtuse angles,and 2 pairs of parallel lines?
Finger [1]
Um i think that it is a rhoubus 
5 0
3 years ago
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Two automobiles leave the same city simultaneously and both head towards another city. The speed of one is 10 km/hour greater th
Veronika [31]

Answer:

5091 Km/hr and 505 km/hr

Step-by-step explanation:

Speed = Distance / Time

Let the speed of first automobile be 'x' and that of the second be 'y'

Since speed of one is 10 times greater than the other. therefore;

⇒ x = 10 y

also let time for faster automobile be 'T' and time for slower auto mobile be 't'

Since first arrive one hour earlier than second, therefore;

⇒ t = T + 1

⇒ For first automobile; x X T = 560 ; substituting for 'x' and 'T'. Therefore;

⇒ 10y (t+1) = 560

⇒ For Second automobile; y X t = 560

⇒ y = \frac{560}{t}

⇒ 10(\frac{560}{t})(t + 1) = 560

⇒ 5600 + \frac{5600}{t} = 560

⇒ 5600 - 560 =  -  \frac{5600}{t}

⇒ t = 1.11 hr

also ; T = 1.11 - 1 = 0.11 hr

Speed of 1st auto  = 560/0.11 = 5091 km /hr

Speed of 2nd auto = 560/1.11 = 505 km/hr

8 0
2 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(3x+18)^{\circ}∠A=(3x+18)
Alex

Answer:

Angle A is 168 degrees and angle B is 12 degrees.

Step-by step explanation:

x=14y

14y+y=180

15y=180

y=12

x=168

5 0
3 years ago
Read 2 more answers
Write an equation and solve. Round to the nearest hundredth where necessary. What is 35% of 63?
DanielleElmas [232]
22.05

35/100=.35 .35x63=22.05
7 0
2 years ago
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance travel
algol [13]

Step-by-step explanation:

as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.

v(t) = 60×ln(t + 1)

V(t) = 60 × integral(ln(t + 1)) between 0 and 5.

integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C

V(t) = 60 × ((t + 1)ln(t + 1) - t + C)

the distance traveled between t = 0 and t = 5 is then

60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =

= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =

= 60×(5.750556815... + C) - 60×C =

= 60×5.750556815... = 345.0334089... ≈ 345 km

7 0
2 years ago
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