Math question please help

Mathematics

2 answers:

Brums [2.3K]3 years ago

4 0

<h3>You add $25,000 and $3,500 .</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~~</h3><h3 /><h3>~</h3><h3 /><h3>~</h3><h3>~~~~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>Hope this wasted your time!</h3>

solong [7]3 years ago

3 0

You add $25,000 and $3,500

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Find the value of the expression if x=12.<br> 1. 3x

Marizza181 [45]

Answer:

Step-by-step explanation:

X equals 12, substitute X for 12

3(12)=36

3 0

3 years ago

Read 2 more answers

CALC BC HELPPP!!!??? 100PTS!!!

lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

$4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}$

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

$\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}$