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damaskus [11]
3 years ago
15

Math question please help

Mathematics
2 answers:
Brums [2.3K]3 years ago
4 0
<h3>You add $25,000 and $3,500 .</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~~</h3><h3 /><h3>~</h3><h3 /><h3>~</h3><h3>~~~~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>~</h3><h3>~</h3><h3 /><h3>~</h3><h3>~</h3><h3>Hope this wasted your time!</h3>
solong [7]3 years ago
3 0
You add $25,000 and $3,500
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3 years ago
Find the unknown measure of the rectangle.<br> Area =28 square centimeters <br>Height =?
taurus [48]
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A = 28  so 28 = 4 * height
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6 0
3 years ago
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A Boxer. needs to lose 3 1/2 kg in a month to be able to complete as a flyweight. In three weeks he lowers his weight from 55.5
Airida [17]

Answer: The boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

Step-by-step explanation:

Since we have given that

Quantity of weight a boxer needs to lose in a month is given by

3\frac{1}{2}\ kg\\\\=\frac{7}{2}\ kg=3.5\ kg

In 3 months, he lowers his weight from 55.5 kg to 53.8 kg.

So, Quantity of weight he lose in three months is given by

55.5-53.8\\\\=1.7\ kg

Number of kilograms the boxer lose in the final week to be able to compete as a flyweight is given by

3.5-1.7\\\\=1.8\ kg

Hence, the boxer lose 1.8 kg in the final week to get able to compete as a flyweight.

4 0
3 years ago
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How many ways can a committee of nine be formed from 10 men and their wives, if no husband serves on it with his wife?​
san4es73 [151]

Answer:

5120

Step-by-step explanation:

divide the entire group into 10 groups where each group has a man and his wife.

number of ways of selecting 9 groups is 10C9 which equals 10 ways

the number of ways selecting 1 person from a group is 2C1 =2 .

So that means the number of ways of selecting 1 person from 9 groups is 2^9=512

number of ways to form the committee is 10*2^9=5120

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3 years ago
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Nady [450]
The second choice is the answer
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3 years ago
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