For this problem, the answer is choice A.
Answer:
24
Step-by-step explanation:
So, Dersan's path is a right triangle. You have to find the last side. You can use the triples or 6^2+8^2=c^2 but I'll use a triple.
3,4,5.
The last side is 10.
6+8+10=24
hope this helped!
Let the cost of 1 notebook be x and the cost of 1 binder be y.
4 notebooks and 3 binders would cost 23.5
Therefore, 4x + 3y = 23.5 (1)
7 notebooks and 6 binders would cost 44.5
Therefore, 7x + 6y = 44.5 (2)
Multiply the first equation by 2.
8x + 6y = 47 (3)
(3) - (2) gives
x = 2.5
Substitute the value of x in (1), we get,
4(2.5) + 3y = 23.5
10 + 3y = 23.5
3y = 23.5 - 10
3y = 13.5
y = 13.5/3
y = 4.5
Hence, cost of 5 notebooks and 3 binders is:
5x + 3y = 5(2.5) + 3(4.5)
= 12.5 + 13.5
= 26
Hence, cost of 5 notebooks and 3 binders is $26.
Answer:
P=163,487,500
Step-by-step explanation: P=Ae^(kt)
151000000=145000000*e^(k5)
151000000/14500000=e^(k5)
1.04137931=e^(k5)
Ln 1.04=Ln e^(k5)
0.04=k5
k= 0.008
P=145,000,000*e^(.008*15)
P=145,000,000*e^0.12
e=2.71828
P=145,000,000*1.12749685
p=163,487,500
Answer:
30 belongs to the set of real numbers, the set of rational numbers, the set of whole numbers, the set of natural numbers and the set of integers.
Step-by-step explanation:
