Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
Given that, ABCD is a quadrilateral, segment AB is congruent to segment CD, ∠1 is congruent to ∠2.
We need to prove that ABCD is a parallelogram.
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How to prove a given quadrilateral is a parallelogram?</h3>
If one pair of opposite sides of a quadrilateral are both parallel and congruent, then it’s a parallelogram.
From the given quadrilateral ABCD:
AB=CD (Given)
∠1=∠2 (Given)
AC=AC (Diagonal)
From ASA congruency ΔABC and ΔADC are congruent.
By CPCT, AD=BC and ∠ABC=∠ADC.
Since opposite angles and sides are equal, then the quadrilateral ABCD is a parallelogram.
To learn more about parallelogram visit:
brainly.com/question/1563728.
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Answer:
The length of XY is 17
Step-by-step explanation:
Given that X is midpoint of line WY
WX=3x-1
WY=10x-26
To find XY:
Given WY is straight line and X is midpoint of line WY
We can write as
WX+XY=WY
(3x-1)+XY=(10x-26)
XY=7x-25
Also, WX=XY
(3x-1)=(7x-25)
-1+25=7x-3x
4x=24
x=6
The length of XY is 7x-25=7(6)-25=42-25=17
Your answer is Y= 2x (a) + 4 (e)
The y intercept is 4 and the slope is 2
what number can be multiplied by itself to get 49? 7
F(x)=-4(8)-5=
F(x)=-32-5=
F(x)=-37