Answer:
am very sure that no boxes 3-5 are applicable,
hope that helps
Answer:
the probability the car was actually blue as claimed by the witness is 33.33%. This is a low percentage and thus, there is a reasonable doubt about the guilt of the client.
Step-by-step explanation:
We are given;
P(car is blue) = 1% = 0.01
P(car is green) = 99% = 0.99
P(witness said blue | car is blue) = 99% = 0.99
P(witness said blue | car is green) = 2% = 0.02
We will solve this by using Bayes’ formula for inverting conditional probabilities:
Thus;
P(car is blue | witness said blue) =
[P(witness said blue | car is blue) × P(car is blue)] / [(P(witness said blue | car is blue) × P(car is blue)) + (P(witness said blue | car is green) × P(car is green))]
Plugging in the relevant values gives;
(0.99 × 0.01)/((0.99 × 0.01) + (0.02 × 0.99)) = 0.3333
Thus, the probability the car was actually blue as claimed by the witness is 0.3333 or 33.33%
Answer:
$54
Step-by-step explanation:
first find 1/4 of $80 and then take that answer and find 10% of that to get your answer