Let a = 693, b = 567 and c = 441 
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under 
693 = 567 x 1 + 126 
567 = 126 x 4 + 63 
126 = 63 x 2 + 0 
Hence, HCF of 693 and 567 is 63 
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63 
441 = 63 x 7+0 
=> HCF of 441 and 63 is 63. 
Hence, HCF of 441, 567 and 693 is 63.
        
             
        
        
        
He should add exact since money is involved
he could also estimate since they are so close together, but he would be off only 2 cents
A
        
                    
             
        
        
        
Answer:
Therefore the required ways are =190
Step-by-step explanation:
Combination: Combination is the number of selection of items from a collection of items where the order of selection does not matter. 
Total number of smartphones =22 
Defective phone = 2
Non defective phone = (22-2) =20
The control inspector randomly test 4 smartphones of which 2 are defective.
Non defective phone = 2
The ways to select 2 non defective phone is

The ways to select 2 defective phone is= 
Therefore the required ways are = (190×1) =190
 
        
             
        
        
        
Answer:
$0.75
Step-by-step explanation:
if Felix wants 1/4 kilogram of marmalade and it cost $3 per kilogram, you divide 3/4= 0.75
 
        
                    
             
        
        
        
Answer:
560/800 = 0.7 pounds per dollar