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Nikitich [7]
3 years ago
11

A garden table and a bench cost $623 combined. The garden table costs $77 less than the bench. What is the cost of the bench?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
3 0

Answer:

the bench costs $546

Step-by-step explanation:

subtract the cost of the table from the total

623 - 77 = 546

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5 0
2 years ago
What is the equation of the line perpendicular to the line y=4/9x-2 that passes through the point (4,3)?
dalvyx [7]
Y - y₁ = m(x - x₁)
 y - 3 = -2¹/₄(x - 4)
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   + 3            + 3
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4 0
3 years ago
Read 2 more answers
A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. 2 marbles are picked at random. What is the probability of fi
taurus [48]
Its a 50%-50% chance that you will be able to pick a red and blue marble without noticing....

8 0
2 years ago
Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
Gennadij [26K]

Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

6 0
3 years ago
Consider the function.
dlinn [17]

Answer:

Statement 3

Step-by-step explanation:

y = -2/3x-24

Make x the subject

y + 24 = -(⅔)x

x = -(3/2)(y + 24)

Intersection variables

f^-1(x) = -(3/2)(x + 24)

Slope: -3/2

No domain restrictions

y-intercept: x = 0

-(3/2)(0+24)

-36

(0,-36)

x-intercepts: y = 0

0 = -(3/2)(x + 24)

x = -24

(-24,0)

Linear function, range is all real values of y

6 0
3 years ago
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