Question

What is the area of a figure that is formed using a parallelogram with base 5.2 meters and height 3 meters, and a semicircle with a radius of 4 meters. Round to the nearest tenth, if necessary.
Question 1 options:

40.7 m2

40.733 m2

33.3 m2

28.2 m2

Answer 1

Answer:

40.7m^2

Step-by-step explanation:

Base×Height= 5.2m×3=15.6m2

Area of semicircle= Pie r^2= Pie×4^2=16×pie

pie×16÷2=8×pie

8×3.14=25.12m2

15.6m2+25.12m2=40.72m2

rounded to nearest tenth=40.7m2

Answer 2

Answer: $40.7\ m^2$

Step-by-step explanation:

Given : A parallelogram has base 5.2 meters and height 3 meters, and a semicircle with a radius of 4 meters.

Area of parallelogram is given by :-

$A_p=b\times h$ , where b is base and h is height of parallelogram.

$=5.2\times3=15.6\ m^2$   (1)

Area of semicircle :-

$A_s=\dfrac{\pi r^2}{2}$, where r is radius.

$=\dfrac{3.14\times4^2}{2}=25.12$     (2)

Now from (1) and (2),. the area of the combined figure will be :-

$A=A_p+A_s\\\\=15.6+25.12=40.72\approx40.7\ m^2$