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mina [271]
3 years ago
12

Rita had $9.00. She spent $3.67 on a magazine.

Mathematics
2 answers:
Ket [755]3 years ago
8 0
She has $5.33 left


$9.00
-$3.67
————
$5.33
jeka943 years ago
3 0

Answer:

the answer is 5.33

Step-by-step explanation:

9.00

-367

--------

5.33

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A carpenter has less than 120 min. to spend painting furniture each day. Today, he has spent 30.5 min. painting a desk. Now he w
FinnZ [79.3K]

Answer:

Hence, a carpenter can paint a maximum of 7 chairs.

Hence, option A is correct.

Step-by-step explanation:

A carpenter has less than 120 min. to spend painting furniture each day.

Today, he has spent 30.5 min. painting a desk.

Now he will paint x chairs, each of which takes 12.5 min.

i.e. he will take a total of 12.5x minutes in painting 'x' chairs.

Also total time spent on painting furniture each day will be equal to time spent on painting a desk and all of the chairs.

Hence,

30.5+12.5x<120 (since the total time he spends on painting is less than 120 mins.)

⇒ 12.5 x<120-30.5

⇒ 12.5 x<89.5

⇒ x<7.16  ( on dividing both side of the inequality with 12.5)

Hence, a carpenter can paint a maximum of 7 chairs.


6 0
3 years ago
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Subtract. Write your answer as a fraction in simplest form.<br><br> 58−(−78)=
chubhunter [2.5K]

Answer:

136

Step-by-step explanation:

8 0
3 years ago
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Please help and explain! *Serious answers only* 30 points :)
topjm [15]
Ok so it's a proportion so this fraction is to this fraction. the smaller rectangle has sides 4 and 12. the larger one has 8 and x. so u set it up 4/12=8/x. the 4 and 8 r both the short sides so u want those on top and 12 and x r long sides so those on bottom. since that is not an answer option u can set it up as 8/4=x/12 because u still keep the variables of the same rectangle from being multipled with each other. so answer #2 is correct
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3 years ago
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Which of the following is a sine of a in the right triangle below
seraphim [82]

Answer:

\frac{5}{13}

Step-by-step explanation:

sine of A = \frac{opposite}{hypotenuse}

opposite = 5

adjacent = 12

hypotenuse = 13

6 0
3 years ago
Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.
zloy xaker [14]

Answer:

y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

x={\pi}{4}

Step-by-step explanation:

We are given that

y'=\frac{2cos2x}{3+2y}

y(0)=-1

\frac{dy}{dx}=\frac{2cos2x}{3+2y}

(3+2y)dy=2cos2x dx

Taking integration on both sides then we get

\int (3+2y)dy=2\int cos 2xdx

3y+y^2=sin2x+C

Using formula

\int x^n=\frac{x^{n+1}}{n+1}+C

\int cosx dx=sinx

Substitute x=0 and y=-1

-3+1=sin0+C

-2=C

sin0=0

Substitute the value of C

y^2+3y=sin2x-2

y^2+3y-sin 2x+2=0

y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}

Hence, the solution y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

When the solution is maximum then y'=0

\frac{2cos2x}{3+2y}=0

2cos2x=0

cos2x=0

cos2x=cos\frac{\pi}{2}

cos\frac{\pi}{2}=0

2x=\frac{\pi}{2}

x=\frac{\pi}{4}

3 0
3 years ago
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