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Julli [10]
3 years ago
10

What is the midpoint of a segment in the complex plane with endpoints at 6 – 2i and –4 + 6i?

Mathematics
1 answer:
igomit [66]3 years ago
7 0
1+2i

to find the midpoint you do it just like you did with rectangular coordinates,
add and divide by 2 the real component and the imaginary components.

\frac{6-4}{2}  =  \frac{2}{2}  = 1

and 

\frac{-2i+6i}{2} = \frac{4i}{2} = 2i
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A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
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<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

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Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

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6 0
2 years ago
Amy spends 30% of her money on a
ioda

Answer:

£2.00

Step-by-step explanation:

Badly worded, as they oftena are! But to me it means

30% spent

60% saved (I.e also taken away and put somewhere else)

10% leftover equals 20p

So 20p equals 10% of what she originally had, so 100% must be £2.00, does that make sense?

8 0
2 years ago
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subtract that from 180 and get 59

Hope this helps!

5 0
3 years ago
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