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Julli [10]
3 years ago
10

What is the midpoint of a segment in the complex plane with endpoints at 6 – 2i and –4 + 6i?

Mathematics
1 answer:
igomit [66]3 years ago
7 0
1+2i

to find the midpoint you do it just like you did with rectangular coordinates,
add and divide by 2 the real component and the imaginary components.

\frac{6-4}{2}  =  \frac{2}{2}  = 1

and 

\frac{-2i+6i}{2} = \frac{4i}{2} = 2i
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I have 3 times as much money as my brother. Our total is $24. How much does each of us have?I have 3 times as much money as my b
musickatia [10]

Answer:

Brother's money  = $6

Money I have  = $18

Step-by-step explanation:

Hi, to answer this question we have to write an equation with the information given:

<em>I have 3 times as much money as my brother: </em>

Money I have = 3x  

Where x is the money that my brother has:

Brother's money = x

<em>Our total is $24 </em>

So, 3x+x =24

Solving for x

3x+x=24

4x =24

x =24/4

x = 6

Replacing with the value of x.

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6 0
3 years ago
If you are given the following stem and leaf display and asked to construct a frequency distribution chart, what would be the wi
Nuetrik [128]

Answer:

Width of intervals: 8

Step-by-step explanation:

We first look at how data is represented in a stem-leaf diagram.

Any number of the left (before -) is the stem and all numbers on right (after -) are the leaves. Each combination of stem and leaf represents one number. For example: 1 - 332 represents: 13, 13, 12.

Our data is as follows:

13, 13, 12, 24, 25, 31, 31, 35, 37, 42, 43, 41, 52, 51, 51, 52

To calculate the width of the frequency distribution chart, we have the following formula:

Class\ width = \frac{Range}{Number\ of\ classes}

The range of any data set = Maximum value in the data set - Minimum value in the data set

Maximum value in this case as seen from the data is 52 and minimum is 12.

Range = 52 - 12 = 40

Since we had only 5 stems in the data, we shall use that as the number of classes required in the frequency distribution chart.

Class\ width = \frac{40}{5}  = 8

Hence, the class width in this data set will be 8.

To make the intervals, we begin from the minimum value and add 8 to it. The intervals will be:

12 - 20

20 - 28

28 - 36

36 - 44

44 - 52

Observe, that all the values of the stem lie within each interval.

For example, there are 3 values for stem 1: 12, 13, 13 and each lie in the first interval 12 - 20.

Next, the values of stem 2 are 24 and 25. Each of these value lie in the second interval 20 - 28; and henceforth.

8 0
3 years ago
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