There is no m in the diagram showed
If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity. The sum of the multiplicities is the degree
Answer:

And we can calculate the deviations from each value like this:






And the mean absolute deviation would be:

Step-by-step explanation:
For this case we have the following dataset given:
101.5 98.7 95.4 92.3 109.8 104.7
We can calculate the mean with the following formula:

And replacing we got:

And we can calculate the deviations from each value like this:






And the mean absolute deviation would be:

Answer:
36 cups of flour
Step-by-step explanation:
if 3 cups of flour=8 ounces.what about 96 onces you cross multiply
Your answer would be:
596.64 = 596.640
Reasoning= If you just take away the zero from 596.640 you would have the same answer as 596.64. Now if you add a zero to 596.64 you still would have the same answer, therefore they are equal.
Hope this helps! (: