All categories

3 years ago

A box contains 17 marbles, 13 blue marbles, and 23 white marbles. What is the part-whole ratio of red marbles in the box.

1 answer:

6 0

Since the ratio is part-Whole, first you need to find the whole. If you add all of the marble colors together (17+13+23) you get the total marbles (53) in the box. The ratio of red marbles to the total would be 17 to 53.

You might be interested in

2t+8 > -4 (t+1)<br> THE > HAS A LIL LINE UNDER IT :)<br> > = ____<br> _

lara31 [8.8K]

2t + 8 ≥ -4(t+1)

PEMDAS

2t + 8 ≥ -4t - 4

2t + 12 ≥ -4t

12 ≥ -6t

-2 ≤ t

7 0

3 years ago

Plss help mehhhhhhhhhhh pls

polet [3.4K]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Any value of X makes the statement true, meaning the solution is all real numbers.

8 0

2 years ago

3) The width is changed by a scale factor of . What is the new volume? 10 cm 15cm 5 cm

MrRa [10]

I think the answer is A i’m sorry if it’s wrong i’m not for sure.

6 0

3 years ago

PLEASE ANSWER FAST!! FIRST CORRECT ANSWER MARKED BRAINLIST. I NEED TO PASS THIS CLASS

soldier1979 [14.2K]

Answer:

6900%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Could someone answer and explain these please? Thank you!

Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

$x=(10 \times t)+(1 \times u)$

$x=10t+u$

The two digit number 'y' is obtained by reversing the digits of x.

So, $y=(10 \times u)+(1 \times t)$

$y=10u+t$

Now, the value of x-y is expressed as:

$x-y=(10t+u)-(10u+t)$

$x-y=10t+u-10u-t$

$x-y=9t-9u$

$x-y=9(t-u)$

So, $9(t-u)$ is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = $\frac{a}{1-r}$

Since, the sum of the given infinite geometric series = 200

Therefore, $\frac{a}{1-r}=200$

Since, r=0.15 (given)

$\frac{a}{1-0.15}=200$

$\frac{a}{0.85}=200$

$a=0.85 \times 200$

a=170

The nth term of geometric series is given by $ar^{n-1}$ .

So, second term of the series = $ar^{2-1}$ = ar

Second term = $170 \times 0.15$

= 25.5

So, the second term of the geometric series is 25.5

Step-by-step explanation:

8 0

3 years ago