Answer:
The question is incomplete, it lacks the mRNA sequence. The sequence is as follows:
5′−AUGGCAAGAAAA−3′
The answer is Met-Ala-Arg-Lys
Explanation:
Gene expression in living organisms involves the process of transcription and translation. Transcription is the synthesis of a complementary strand of mRNA from a DNA template while translation involves using the transcibed mRNA as a template to synthesize amino acid sequence (proteins).
In the RIBOSOME, where the synthesis of protein occurs, the mRNA nuceleotide sequence is read in a group of three nucleotides called CODON. Each codon specifies a particular amino acid. The collection of all codons is the genetic code. Hence, for a specific mRNA sequence that reads 5′−AUGGCAAGAAAA−3′. The nucleotides will be read three at a time starting with AUG which is a codon that encodes METHIONINE.
Next, GCA is a codon that encodes ALANINE
Next, AGA is a codon that encodes ARGININE
Finally, AAA is a codon that encodes LYSINE.
Hence, the amino acid sequence using the above mRNA sequence, will read: Met-Ala-Arg-Lys
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
Answer:
Yes
Explanation:
subsidence will dry out an air mass by adiabatic or compression heating.
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The answer is Glycerol
Hope this helps
