Question

I'm stuck on a MathsWatch question. I've started it but I need some help to finish it please. Thank you! It's out of 5 marks, so far I've only managed to get 1. Again, thanks.

Answer 1

We have area of the rectangle:

$fg=120$

Area of the triangle:

$\frac 1 2 f \times 3 = 135-120$

Solve away:

$f = \frac 2 3(15) = 10$

$g= \dfrac{120}{f}=12$

Answer: f=10, g=12

Check: trapezoid area

$A = \frac 1 2(12+15)10 = 5(27)=135 \quad\checkmark$