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LenaWriter [7]
3 years ago
7

Two long jumpers competed in a world-class track meet. The first athlete jumped a distance of 28.65 feet, and the second athlete

reached a distance of 24.25 feet.
The first athlete jumped
feet farther than the second athlete.
Mathematics
2 answers:
ladessa [460]3 years ago
7 0
Hello! This is actually pretty easy to solve, all you have to do is subtract 28.65 from 24.25 So when you subtract 5 from 5, you get zero. When you subtract 6 from 2, you get 4. When you subtract 8 from 4, you get 4, and when you subtract 2 from 2 you get zero. So all you do is take out the zeros and put the decimal point in the same place it was in before, and this should leave you with your answer!

I hope this helped!

I am, yours most sincerely,
SuperHelperThingy
Drupady [299]3 years ago
4 0

Answer:

The first athlete jumped  4.50 feet farther than the second athlete

Step-by-step explanation:

Two long jumpers competed in a world-class track meet.

Now, Distance covered by first athlete on jumping = 28.65 feet

Also, Distance covered by second athlete on jumping = 24.25 feet

We need to calculate the distance by which the first athlete jumped father from the second athlete

⇒ Required distance = 28.65 - 24.25

⇒ Required distance = 4.50 feet

Hence, The first athlete jumped  4.50 feet farther than the second athlete

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f'(x) = -10/x²         f'(-2) = -10/(-2)²

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