Ask question

Ask question

All categories

3 years ago

12

A construction manager needs 12 workers to complete a building project in 54 days. Find in terms of T the number of workers need

ed to complete the same project in T days

1 answer:

ch4aika [34]3 years ago

7 0

Answer:

<h3>2T/9</h3>

Step-by-step explanation:

A construction manager needs 12 workers to complete a building project in 54 days, we can write;

12 workers = 54 days

T find the number of workers needed to complete the same project in T days, we will write;

x workers = T days

Divide both equations

12/x = 54/T

Cross multiply

12T = 54x

x = 12T/54

x = 2T/9

Hence the number of workers needed to complete the same project in T days is 2T/9 workers

You might be interested in

Solve for n<br> n +8,7 = 16,2<br> on=65<br> on=75<br> On=85<br> On = 24.9

Usimov [2.4K]

Answer:

There is not enough to solve.

Step-by-step explanation:

7 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

4 years ago

Mr. Reeves buys granola bars to sell at the concession stand. He predicts that the concession stand will sell 25 granola bars at

Bezzdna [24]

Answer:

He should buy 4 boxes

Step-by-step explanation:

25 divided by 8 is 3.125, but you want to have enough so the least amount you can buy is 4.

4 0

3 years ago

Read 2 more answers

Simplify each of the following powers of i. i^99=

Scorpion4ik [409]

I= sqrt (-1)

If the power is
- even then the value could be -1 or 1
-odd then the value could be -i or i

99 is odd so now is
-i if (99+1)/2 is even or is
i is (99+1)/2 is odd

Now check (99+1)/2= 100/2= 50,
50 is even so
i^99 = -i

8 0

3 years ago

Read 2 more answers

Burl and Paul paint signs together on a scaffold. Compared to their weights plus the weight of the scaffold, the sum of tensions

tatyana61 [14]

Answer:

equal

Step-by-step explanation:

If the scaffold is not accelerating either upward or downward, the sum of upward support forces is <em>the same as</em> the sum of downward weights being supported.

5 0

3 years ago