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mamaluj [8]
3 years ago
13

A sporting goods sold 2.5 times as many football as basketball last year drag footballs to represent the number of football sold

for every 2 basketball sold.
Mathematics
1 answer:
arlik [135]3 years ago
4 0

Answer:

<em>5 footballs were sold for every 2 basketballs sold.</em>

Step-by-step explanation:

2.5 times as many football as basketball was sold last year

This can be represented as

1 basket ball sold = 2.5 footballs sold

for every 2 basketball sold, number of football sold = 2.5 x 2 = <em>5 footballs</em>

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Answer:

10

Step-by-step explanation:

25 x 12 = 300$ worth of adult tickets sold

360 - 300 = 60$ worth of child tickets sold

60/6 = 10 tickets

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Which ordered pair is a solution to the system of inequalities?
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Answer: The answer is C. Hope this helps :)

Step-by-step explanation:

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For the graph of the equation below, the ___ is the major axis.
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3 years ago
Plzz help on Question B nd C plzz​
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Answer:

see explanation

Step-by-step explanation:

(b)

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3 0
4 years ago
The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has
ANTONII [103]

Answer:

The voltage in exponential form would be (\frac{3}{5})^3.

The original voltage in the circuit is \frac{3}{5} of a volt.

Step-by-step explanation:

Let x represent the original voltage.

We have been given that the voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times.

The original voltage multiplied by itself for 3 times would be x\cdot x\cdot x=x^3.

Now, we will equate x^3 with 27/125 as:

x^3=\frac{27}{125}

We know that 27 is cube of 3 and 125 is cube of 5, so we can represent our equation as:

x^3=\frac{3^3}{5^3}

x^3=(\frac{3}{5})^3

Therefore, the voltage in exponential form would be (\frac{3}{5})^3

Now, we will take cube root of both sides to find original voltage in the circuit as:

\sqrt[3]{x^3} =\sqrt[3]{(\frac{3}{5})^3}

Using property \sqrt[n]{a^n} =a, we will get:

x =\frac{3}{5}

Therefore, the original voltage in the circuit is \frac{3}{5} of a volt.

6 0
4 years ago
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