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kolbaska11 [484]
3 years ago
13

The temperature a 9 a.m. is 2 degrees. the temperature rises 3 more degrees by noon. which expression describes the temperature

at noon
.A 2+3

.B 2+(-3)

.C -2+(-3)

.D -2+3
Mathematics
2 answers:
dsp733 years ago
6 0
A. 2+3°
Is the expression that describes the temperature at noon.
mafiozo [28]3 years ago
5 0
A. 2+3
Hope this helps!
If you need anymore help, feel free to message me. :)
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Answer for x: 3x-2=-1​
Lilit [14]

Answer:

Step-by-step explanation:

3x-2=-1​

3x = -1 + 2

3x = 1

x = 1/3

6 0
3 years ago
How many solutions can be found for the set of linear equations? 7(x + 2) and 7x + 14
castortr0y [4]
7(x + 2) = 7x + 14...and 7x + 14

there will be infinite solutions because these 2 equations are the same line
8 0
4 years ago
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A 99% confidence interval for the sugar content (per 5 oz. serving) of a shipment of strawberries is 5.9 to 8.3 grams.
gavmur [86]

Answer:

Sample mean = 7.1

Margin of error = 0.465

Step-by-step explanation:

Formula for confidence interval is;

CI = x¯ ± zE

Where;

x¯ is sample mean

z is critical value at confidence level

E is margin of error.

z for 99% Cl is 2.58

We are told the CI is 5.9 to 8.3.

Thus;

5.9 = x¯ - 2.58E - - - - (1)

8.3 = x¯ + 2.58E - - - - (2)

Add both equations together to get;

14.2 = 2x¯

x¯ = 14.2/2

x¯ = 7.1

Put 7.1 for x¯ in eq 1 to get;

5.9 = 7.1 - 2.58E

7.1 - 5.9 = 2.58E

E = 1.2/2.58

E = 0.465

5 0
3 years ago
On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi
blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

{22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19}  + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069

I hope that works for you!

4 0
3 years ago
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schepotkina [342]
0.8 is smaller than 0.81 by the 0.01
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