He has a 26% of getting a strike, which means he has a 74% chance of not getting a strike ( 100% - 26% = 74%).
Multiply the chance of not getting a strike by the number of attempts:
0.74 x 0.74 x 0.74 x 0.74 x 0.74 = 0.22
The answer is B) 0.22
The probability of making a free throw is 77%, the probability of not making one would be 23% ( 100% - 77% = 23%).
Add the probability of making the first one ( 0.77) by the probability of making the second one multiplied by the probability of missing the second one ( 0.77x 0.23)
0.77 + (0.77 x 0.23)
0.77 + 0.18 = 0.95
The answer is D) 95%
we have been asked to find the sum of the series
As we know that a geometric series has a constant ratio "r" and it is defined as
The first term of the series is 
Geometric series sum formula is
Plugin the values we get
On simplification we get
Hence the sum of the given series is 
Answer:
Sample Space = {A, B, C, D, E, F}.
Sample space for choosing C to F = {C, D, E, F}.
Step-by-step explanation:
All six letters are included in the first set of possible outcomes.
Four letters (C to F) are included in the second set of possible outcomes.
5 children so you have 2^5=32 possibilities to "assign" genders
P(3 girls):
how many possibilities are there to "assign" the 3 girl-genders to the 5 children? the first girl has 5 possibilities then the next 4, 3 -> 5*4*3=60
but these possibilities include orders of assigned genders, while children 1-5 might differ the gender "girl" is always the same so we have the remove the orderings of the 3 girl-gender assignments which is 3*2*1=6
if we divide 60/6 we get 10 possibilities to have 3 girls, so what is the resulting chance? the 10 possibilities divided by the total 32 possibilities: 10/32=5/16=P(3 girls)=P(2 boys)
this is a bit of lengthy way of saying "use the binomial coefficient" equation/explaining it a bit which is (n!)/(k!(n-k)!) with n=5, k=3:
5*4*3*2*1/((3*2*1)*(2*1))=
5*4*3*2/(3*2*2)=
5*4*3*2/(3*4)=
5*2=
10 possibilities again
P(girls>=4)=P(boys<=1)=P(boys=1)+P(boys=0)
(or P(girls=4)+P(girls=5))
P(boys=0) is the easy case: simply multiply the chance of getting a girl 5 times: (1/2)^5=1/32
P(boys=1)= again the binomial coefficient with n=5 and k=1:
5*4*3*2*1/((1)*(4*3*2*1))=
5*4*3*2/(4*3*2)=
5 possibilities
so the P(boys=0)=1 possibility + P(boys=1)=5 possibilities totals to 6 possibilities
again the chance is the 6 possibilities divided by all 32 possibilities: 6/32=3/16
P(alternate gender starting with boy): when thinking about the possibilities then there is only a single way to build that order: bgbgb, so one possibility
knowing there is only one way we already know P(alternate...)=1/32 by again dividing by the total amount of possibilities
the alternative way would be to multiply P(boy)*P(girl)*P(boy)*P(girl)*P(boy)=(1/2)^5= 1/32 again
