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3 years ago

Jimmy is about to pick a marble from the jar. How likely is it that he will pick a blue marble?

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

depends on how many different colors there are in the jar and how many marbles there are.

Step-by-step explanation:

Allisa [31]3 years ago

4 0

Answer:

HAY MUCHAAAAAAAS POSIBILIDADES

Step-by-step explanation:

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The expression c(16x + 14) is equivalent to 32x + d.

pychu [463]

Answer:

c = 2

d = 28

Step-by-step explanation:

Please see the attached file for explanation

7 0

3 years ago

Find the equation of the line that passes through the given points

uranmaximum [27]

First you need to figure out the slope:
y2-y1/x2-x1=(1+5)/(-5-7)=-1/2

y+5=-1/2(x-7)
y=-1/2x-3/2

6 0

3 years ago

Which expression is equivalent to -36 - 8?

Deffense [45]

-36-8 = -44

-36+(-8) = -44
third option

7 0

2 years ago

Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100. How much money will you save

Dmitriy789 [7]

it is given in the question that

Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100.

For Alpha, cost of 1 brochure is

$= \frac{100}{400} = $0.25$

For Omega,

Cost of 1 brochure is

$= \frac{100}{1000} = 0.10$

So choosing Omega printing, you will save

$= 0.25-0.10 = $0.15$

on each brochure .

6 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago