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3 years ago

Jimmy is about to pick a marble from the jar. How likely is it that he will pick a blue marble?

Mathematics

2 answers:

Sav [38]3 years ago

8 0

Answer:

depends on how many different colors there are in the jar and how many marbles there are.

Step-by-step explanation:

Allisa [31]3 years ago

4 0

Answer:

HAY MUCHAAAAAAAS POSIBILIDADES

Step-by-step explanation:

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Please help me solve

Lana71 [14]

Answer:

C. 30 ft

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

When we draw out a picture, we should see that we use the Pythagorean Theorem to help solve our missing height:

10² + b² = 32²

b² = 32² - 10²

b = √924

b = 2√231 or 30.3974

Round that to 30 feet.

6 0

3 years ago

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Alisa is choosing new tile for the floor in her dining room which is in the shape of a square with side lengths x feet. The tile

inna [77]

Answer:

A F = 3.39 per sq ft. B 37.29 C 77.97

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2 years ago

which geometric object is defined as the set of all points in a plane that are equidistant from the two sides of a given angle

Volgvan

Answer:B.) Bisector Of An Angle

Step-by-step explanation:

5 0

3 years ago

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The following triangles are similar by SAS~

svet-max [94.6K]

Step-by-step explanation:

sides:91/12=42/26

angles:LMN=LBA and MNL=BAL

5 0

3 years ago

Please help I am so lost!!!

ASHA 777 [7]

$\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\$

$\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)$

4 0

3 years ago