Answer:

Step-by-step explanation:
Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.

<h3>
<u>Related</u><u> </u><u>Infor</u><u>mation</u><u> </u><u>:</u><u>-</u><u> </u></h3>
• The sum of n terms of an AP is
• nth term of an AP is given by ,

9514 1404 393
Answer:
C. y is 6 less than x
Step-by-step explanation:
It is not hard to check.
A. 6 times x is 6×8 = 48, not 2
B. 6 times y is 6×2 = 12, not 8
C. 6 less than 8 is 2; 6 less than 9 is 3
D. 6 more than 8 is 14, not 2
__
The relation described in C matches the table.
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
The answer is 3.
Step-by-step explanation:
Given that the Indices Law is,


So the expression is :




