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Nastasia [14]
3 years ago
11

Is 75/100 less, more than, or equal to 8/10

Mathematics
2 answers:
Sauron [17]3 years ago
6 0
75/100 is less than 8/10.
8/10 can be equivalent to 80/100.

75/100 is less than 80/100.

Hope this helps.
brilliants [131]3 years ago
3 0
Use your calculator to make the division : 75/100 = .75 & 8/10 = .80. Therefore 8/10 is more than 75/100.
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If 5/8 is multiplied by 4/5 will the product be greater than the two factors? Explain.
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Step-by-step explanation:

4/5 is less than 1, so multiplying 5/8 by 4/5 results in a product smaller than the two factors.

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To convert 2/3 into an equivalent fraction with a denominator of 18, we could multiply only the denominator of 2/3 by.
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James and Sarah went out to lunch. The price of lunch for both of them was $60. They tipped their server 10% of that amount.
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$66

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3 0
2 years ago
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PLZ HELP Simplify the rational expression. State any excluded values. 2x/-5x+x^2
Bas_tet [7]
(2x/-5x)+x^2
(x(2)/(x(-5))+x^2

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6 0
3 years ago
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What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
Read 2 more answers
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