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3 years ago

In the diagram, JKLM∼EFGH. Find the scale factor of EFGH to JKLM

Mathematics

1 answer:

mote1985 [20]3 years ago

5 0

The answer is k= 2.5

Explanation: Rotating the shape will show that one side is 20:8. Divide these together and you get 2.5.

Hope this helps

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How should this model be completed to represent 605 ÷ 18?

rosijanka [135]

Answer:

Check the attached image

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1 year ago

Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â Suppose a small group of 11 Allen's humming

alexira [117]

Answer:

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=3.15$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=0.38$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.80 or 80%, the value of $\alpha=0.2$ and $\alpha/2 =0.1$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that $z_{\alpha/2}=1.28$

Now we have everything in order to replace into formula (1):

$3.15-1.28\frac{0.38}{\sqrt{11}}=3.003$

$3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297$

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

$ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147$

8 0

3 years ago

Based on the pattern in the table what is the value of A

Arlecino [84]

Answer D, 1/64

The denominator has a pattern , if you look through it carefully each denominator is multiply by 2. There for you multiply 32 x 2 which gives you 64 so it’s 1/64. If you wanna confirm it , you could use a calculator to check your answer.

5 0

3 years ago

Read 2 more answers

The center of a circle is at (2, -5) and it's radius is 12. What is the equation of the circle?

Svetach [21]

The equation for a circle is (x-h)^2 +(y-k)^2=r^2
You just have to plug in your coordinates h is the x and k is the y.
The r is radius squared.
so, (x-2)^2+(y-(-5)^2=144
You have to be careful of those tricky negative values. When you distribute the y-(-5) it turns into y+5.
So your answer is D.

8 0

3 years ago

Read 2 more answers

Which of the following points is between 2 and -3 on the number line?<br> -4 3 -2 -5

lions [1.4K]

Answer:

-2

Step-by-step explanation:

-5 -4 -3 <u>-2</u> -1 0 1 2 3 4 5

3 0

3 years ago