<span>Rh-positive fetus and an Rh-negative mother condition occur.</span>
Parental Phenotypes: "Yellow-Smooth", "Yellow-Wrinkled", "Green-Smooth", "Green Wrinkled".
Parental Genotypes: SsGg × SsGg
Parental Gametes: SG, Sg, sG, sg
<span>
Smooth/Green </span>= S-G- = 9
<span>
Winkled/Green </span>= ssG- = 3
Smooth/Yellow = S-gg = 3
Wrinkled/Yellow = ssgg = 1
Ratio would be: 9: 3: 3: 1
Hope this helps!
Answer:
It provides for the maturation and release of a fertilizable oocyte
Explanation:
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Answer:
Explanation:
In a lake, oxygenic phototrophs produce new organic material as well as O₂. If primary production rates are very high, the resultant excessive organic matter production can lead to bottom-water O₂ depletion from respiration and the development of anoxic conditions. This in turn stimulates anaerobic metabolisms, including anaerobic respirations and fermentations.
Organic matter that is not consumed in surface layers sinks to the depths and is decomposed by anaerobes.
Answer:
25% heterozygous tall
Explanation:
If we take the F1 generation as parents and let them self-fertilise, we have 4 crosses.
The first one for homozygous tall, then we have 100% AA.
The second and third one for heterozygous tall and we have 25% AA, 50%Aa and 25%aa for each of them.
The last one would be for dwarf, and we'll have 100%aa.
Adding all of them, we'll have
AA = 100 + 25 + 25 = 150%
Aa = 50+50 = 100%
aa = 100 + 25 + 25 = 150%
as we had 4 crosses, so dividing the total percentages by 4, we'll have,
AA = 37.5%
Aa = 25%
aa = 37.5%
:. The percentage of heterozygous tall would be 25%.
Hope it helps:)
