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3 years ago

Directions: Calculate the percent increase or decrease between the starting and ending

Mathematics

2 answers:

Sveta_85 [38]3 years ago

7 0

I'll do the first two to get you started

===============================================

Problem 1

A = 3 = starting value

B = 10 = ending value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (10-3)/3 ] * 100%

C = (7/3) * 100%

C = 2.3333333 * 100%

C = 233.33333%

C = 233.3%

The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.

<h3>Answer: 233.3% increase</h3>

===============================================

Problem 2

A = 9 = start value

B = 20 = end value

C = percent change

C = [ (B - A)/A ] * 100%

C = [ (20-9)/9 ] * 100%

C = (11/9)*100%

C = 1.2222222222*100%

C = 122.22222222%

C = 122.2%

<h3>Answer: 122.2% increase</h3>

mezya [45]3 years ago

4 0

The answer is 3 and end

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Answer:

Step-by-step explanation:

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2 years ago

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Answer: The perimeter is 30ft.

Step-by-step explanation:

Let's define:

L = length of the longer side.

S = length of the shorter side.

P = perimeter

we know that for a common rectangle:

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We aso know that:

L = 2ft + (1/3)*P

S = (1/10)*P

L = S + 9ft.

So we have a system, let's find the perimeter only using this system (So i will ignore the equation for the perimeter of a rectangle)

First, we can replace the third equation in the first equation, now we have a system with only two equations:

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Now we can replace the second equation in the first equation, and get:

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Now let's solve this for P.

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3 years ago

A visitor makes a list of 11 sights he’d like to see. He is determined to visit at least 8 of these. How many possible choices d

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Using the combination formula, it is found that he has 232 choices.

The order in which the sights are seen is not important, hence the <em>combination formula </em>is used to solve this question.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem, the choices are 8, 9, 10 or 11 sights from a set of 11, hence:

$T = C_{11,8} + C_{11,9} + C_{11,10} + C_{11,11} = \frac{11!}{3!8!} + \frac{11!}{2!9!} + \frac{11!}{10!1!} + \frac{11!}{0!11!} = 232$

He has 232 choices.

You can learn more about the combination formula at brainly.com/question/25821700

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2 years ago

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Eliminate parentheses and collect terms.

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