Answer:
The quadratic function whose graph contains these points is 
Step-by-step explanation:
We know that a quadratic function is a function of the form
. The first step is use the 3 points given to write 3 equations to find the values of the constants <em>a</em>,<em>b</em>, and <em>c</em>.
Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.



We can solve these system of equations by substitution
- Substitute


- Isolate a for the first equation

- Substitute
into the second equation



The solutions to the system of equations are:
b=-2,a=-1,c=-2
So the quadratic function whose graph contains these points is

As you can corroborate with the graph of this function.
(4,3)(2,2)
slope = (2 - 3) / (2 - 4) = -1/-2 = 1/2
y = mx + b
slope(m) = 1/2
use either of ur sets of points...(4,3)...x = 4 and y = 3
now we sub and find b, the y int
3 = 1/2(4) + b
3 = 2 + b
3 - 2 = b
1 = b
so ur equation is : y = 1/2x + 1 <==