Yes. The situation is defined by a linear function.
<u>Solution:</u>
Given, The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers earnings per hour.
Is this situation defined by a linear function?
Yes, the above given situation is defined by a linear function.
Now, let us see the linear equation for above situation
Let the number of hours worked by manager be "x", and cost per hour be "c" and total salary be "y"
Then, total salary is given as,
Total salary = $ 30 bonus + number of hours worked
cost per hour

Above equation is a linear equation as "c" is constant ( cost per hour )
Hence, the given situation can be defined by linear function.
X= -b over 2a = --6 over 2×1=3
y=3²-6(3)-7=-16
vertex is (3,-16)
axis of symmetry is 3
Answer:
6
Step-by-step explanation:
Answer:
what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.
Step-by-step explanation:
In this question, we are asked to calculate if the prediction made by an equation modeled is correct.
Firstly let’s look at the equation in question;
y = 3t - 6
where y is the snow depth and t is the number of hours after midnight.
now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.
let’s plug the value of t as 7 into the equation
y = 3(7) - 6
y = 21-6
y = 15 inches
according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.