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zloy xaker [14]
4 years ago
5

Have no idea how to do it

Mathematics
1 answer:
dalvyx [7]4 years ago
6 0

\bf 2)\\\\ 3+-5\implies 3+(-5)\implies 3+(-3-2)\implies ~~\begin{matrix} 3-3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-2\implies -2 \\\\\\ 9)\\\\ -5+(-6)\implies -5+(+5-11)\implies ~~\begin{matrix} -5+5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-11\implies -11 \\\\\\ 11)\\\\ 2+(-7)\implies 2+(-2-5)\implies ~~\begin{matrix} 2-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-5\implies -5

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Your answers would beX = -1/5
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What is the soulution of -(-5-6x) = 4(5x+3)?
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Suppose GH = JK , HI = KL and <1 =
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3 years ago
Find the slope of the line passing through the points A(6, –5) and B(–5, –7).
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6 0
3 years ago
Read 2 more answers
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi
nalin [4]
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^{2}+(5-2)^{2}}
D=\sqrt{(4)^{2}+(3)^{2}}
D=\sqrt{16+9}
D=\sqrt{25}
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0
3 years ago
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