Answer:
A subunit of Rubisco takes approximately 0.33 s to perform one reaction
Explanation:
The kcat it's a kinetic first order constant that related the properties of the enzyme substrate complexes in a mechanisms and represents the overall first order process of the transformation of the substrate-enzyme complex into product.
Also kcat can be seen as the turnover number of an enzyme, representing the maximum number of substrate molecules that the enzyme can transform into product per time unit and per active site.
If the kcat is 3 s^-1, it means Rubisco can catalyse the transformation of 3 substrate molecules per second.
So, the time that takes a single reaction, should be the inverse of kcat.
To see it more clearly, the time needed for a single reaction is the time observed divided by the number of reactions done during that time.
In other words:
3 reactions ----------- 1 s
1 reaction -------------- x
- x=1 reaction/3 reactions.s^-1 = 1/kcat = 1/3 s ~ 0.33 s
So the time that takes one Rubisco subunit to do one reaction is approximately 0.33 s
Osmosis only talks about water molecules
Diffusion talks everything other then the water molecules.
So,
Osmosis : water molecules travel from a region of a higher water potential to a region of lower water potential through a partially permeable membrane via osmosis
Diffusion : Travels from a region of higher concentration to a region of lower concentration through a partially permeable membrane via diffusion
Answer:
Option (d).
Explanation:
Equilibrium may be defined as the state of the equality on both the sides of the reaction. Different types of equilibrium are physical equilibrium, chemical equilibrium and dynamic equilibrium.
Chemical equilibrium may be defined as the equilibrium in which the reactants and products concentration remains constant with time. The rate of the backward reaction is equal to the rate of forward reaction.
Thus, the correct answer is option (d).
