This is how you solve this problem:
.10d + .05n = 5.25
(plug in the number of dimes we have)
(21 x .1) + .05n = 5.25
(multiply number of dimes x value of the dime)
2.10 + .05n = 5.25
(subtract 2.10 from both sides)
.05n = 3.15
(divide both sides by .05 to get the number of nickels)
n = 63 nickels
Hope this helps!
Answer:
4/3
Step-by-step explanation:
4/10 / 3/10
4/10 * 10/3
The 10s cancel out and you are left with
4/3
6y-4=4y+2
2y=6, so y=3.
Plugging it in, you get that AC equals 4*3+2=14.
This is an isosceles triangle.
2 | <u>5</u><u>5</u><u>0</u><u>,</u><u>7</u><u>5</u><u>0</u><u>,</u><u>9</u><u>0</u><u>0</u>
2 | <u>2</u><u>7</u><u>5</u><u>,</u><u>3</u><u>7</u><u>5</u><u>,</u><u>4</u><u>5</u><u>0</u>
3 |<u> </u><u>2</u><u>7</u><u>5</u><u>,</u><u>3</u><u>7</u><u>5</u><u>,</u><u>2</u><u>2</u><u>5</u>
<u>3</u><u> </u>| <u>2</u><u>7</u><u>5</u><u>,</u><u>1</u><u>2</u><u>5</u><u>,</u><u>7</u><u>5</u>
5 | <u>2</u><u>7</u><u>5</u><u>,</u><u>1</u><u>2</u><u>5</u><u>,</u><u>2</u><u>5</u>
5 | <u>55,25,5</u>
5 | <u>1</u><u>1</u><u>,</u><u>5</u><u>,</u><u>5</u>
11 | <u>1</u><u>1</u><u>,</u><u>1</u><u>,</u><u>1</u>
LCM:-2×2×3×3×5×5×5×11=49500