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Nutka1998 [239]
4 years ago
6

Write the ka expression for an aqueous solution of nitrous acid:

Chemistry
1 answer:
lina2011 [118]4 years ago
4 0
Balanced chemical reaction (dissociation): HNO₂(aq) ⇄ H⁺(aq) + NO₂⁻(aq).
Answer is: Ka = [NO₂⁻]·[H⁺] / [HNO₂].
Ka - acid dissociation constant.
[HNO₂] - equilibrium concentration of nitrous acid.
[NO₂⁻] - equilibrium concentration of nitrite anions.
[H⁺] - equilibrium concentration of hydrogen cations.
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which equation is setup correctly to determine the volume of a 1.5 mol sample of oxygen gas at 22 degrees Celsius and 100 kPa
rjkz [21]
Hello!

We have the following data:


v (volume) = ? (in L)
n (number of mols) = 1,5 mol
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First let's convert the temperature on the Kelvin scale, let's see:
TK = TºC + 273,15
TK = 22 + 273,15
TK = 295,15

P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm
R (gas constant) = 0,082 atm.L / mol.K

<span>We apply the data above to the Clapeyron equation (gas equation), let's see:

</span>P*V = n*R*T

0,987*V = 1,5*0,082*295,15

0,987V = 36,30345

V =  \dfrac{36,30345}{0,987}

\boxed{\boxed{V \approx 36,78\:L}} \end{array}}\qquad\checkmark

I hope this helps. =)
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Explanation:

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