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3 years ago

Calculate the pH of the buffer

Chemistry

1 answer:

77julia77 [94]3 years ago

5 0

Answer:

Less than 7 so it is going to be acidic.

Explanation:

A buffer solution is one that resists changes in pH when small quantities of an acid or an alkali are added to it. An acidic buffer solution is simply one which has a pH of less than 7. Acidic buffer solutions are commonly made from a weak acid and one of its salts - often a sodium salt.

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Which of these charges has the greatest magnitude

Natalka [10]

Answer:

magnitude means absolute value, so the one that is greastest, like |-7| and |4| even id |-7| is a negative number, but it is still the one farthest away from 0, so |-7| is greater than |4|.

That is the way to find the greatest magnitude, but because I don't know your numbers so I can not answer your question, but this is the way to solve for it.

HOPE THIS HELPS!!!!!!!!!( IF IT DOES <u><em>PLEASE MARK ME AS BRAINLIEST )</em></u>

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3 years ago

Does a spring tide always happen in the season of spring

grin007 [14]

THE SPRING TIDE DOES NOT HAVE ANYTHING TO DO WITH THE SEASON OF SPRING AND IT OCCURS MOSTLY IN THE FALL

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3 years ago

The theoretical yield of ammonia in an industrial synthesis was 550 kg, but only 480 kg was obtained. What was the percentage yi

Klio2033 [76]

We know that when calculating percent yield, we use the equation:

$Percent yield=\frac{Actual yield (A)}{Theoretical yield (T)}$

Since the quantities that we are given in the question are equal, we can just directly divide them to find percent yield:

$Percentyield=\frac{480kg}{550kg} =0.8727*100=87.27$

So now we know that the percent yield of the synthesis is 87.27%.

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3 years ago

Please help me with all the questions and needs to be right thank u

murzikaleks [220]

Answer:

7. b

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Explanation:

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3 years ago

How many milliliters of an aqueous solution of 0.170 M ammonium carbonate is needed to obtain 16.1 grams of the salt

Citrus2011 [14]

There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of

Why?

In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

$(NH_{4})2CO_{3}$

Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

$N_{2}=14g*2=28g\\\\2H_{4}=2*1g*4=8g\\\\C=12.01g*1=12.01g\\\\O_{3}=15.99g*3=47.97g$

We have that the molecular mass of the substance will be:

$MolecularMass=\frac{28g+8g+12.01g+47.97g}{mol}=95.98\frac{g}{mol}$

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:

$mol_{(NH_{4})2CO_{3}=\frac{mass_{(NH_{4})2CO_{3}}}{molarmass_{(NH_{4})2CO_{3}}}$

$mol_{(NH_{4})2CO_{3}=\frac{16.1g}{95.98\frac{g}{mol}}=0.167mol$

Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:

$M=\frac{moles_{solute}}{volume_{solution}}$

$M=\frac{moles_{solute}}{volume_{solution}}\\\\volume_{solution}=\frac{moles_{solute}}{M}$

Now, substituting and calculating, we have:

$volume_{solution}=\frac{0.167mol}{0.170\frac{mol}{L}}\\\\volume_{solution}=0.982L=0.982L*1000=982.35mL$

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.

Have a nice day!

5 0

3 years ago