Answer:
The concentration is [-1 + sqrt(1+0.11t)]/0.1542 M
Explanation:
Let the concentration of CH3CHO after selected reaction times be y
Rate = Ky^2 = change in concentration of CH3CHO/time
K = 0.0771 M^-1 s^-1
Change in concentration of CH3CHO = 0.358 - y
0.0771y^2 = 0.358-y/t
0.0771ty^2 = 0.358 - y
0.0771ty^2 + y - 0.358 = 0
The value of y must be positive and is obtained in terms of t using the quadratic formula
y = [-1 + sqrt(1^2 -4(0.0771t)(-0.358)]/2(0.0771) = [-1 + sqrt(1+0.11t)]/0.1542 M
Answer:
On the opposite side of the rock.
Explanation:
Vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa then the absolute pressure in the chamber and express is 57kpa
Gauge pressure is the pressure relative to atmospheric pressure. Gauge pressure is positive for pressures above atmospheric pressure, and negative for pressures and absolute pressure is the sum of gauge pressure and atmospheric pressure
Here to find absolute pressure atmospheric pressure=92kpa and vacuum gage=35 kpa
Pabsolute pressure=Patmospehric pressure - Pvaccume
92-35=57kpa
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Answer:
The lanthanides and the actinides at the bottom of the table are sometimes known as the inner transition metals because they have atomic numbers that fall between the first and second elements in the last two rows of the transition metals
