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julia-pushkina [17]
2 years ago
13

Gertrude cut a 76-meter rope into two pieces. the long piece was 12 meters longer than the short piece. how long was the short p

iece
Mathematics
1 answer:
7nadin3 [17]2 years ago
7 0
The shorter piece was 32 meters.
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[B]   The ratios in Table B are greater than the ratios in Table A.

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Please help i’m not understanding
ratelena [41]

Answer:

D is not a supported statement

Step-by-step explanation:

Let take them one by one:

A: from table: 0.57; in statement: 0.5

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8 0
2 years ago
Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%
weeeeeb [17]

Answer: a. The system that models this situation is,

x + y = 6 , 8 x + 5 y = 36.

b. Solution is x = 2lb and y = 4lb

where x is the quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Step-by-step explanation:

Let x quantity of 80% of peanuts mixture mix with y quantity of 50% of peanuts mixture for making 60% of peanuts mixture.

Then According to the question,

x + y = 6      --------- (1)

And, 80 % of x + 50 % of y = 60 % of 6

⇒ 0.8 x + 0.5 y = 3.6

⇒ 8 x + 5 y = 36  --------- (2)

Where equation 1) and equation 2) are the required equation which models the given situation.

Now, 8 × equation 1)

We get, 8 x + 8 y = 48 ----------(3)

equation (3) - equation (2)

we get, 3 y = 12

⇒ y = 4

By putting the value of y in equation (2)

we get, x = 2

Thus, he mixed 2 lb of mixture 80/20  and 4 lb of mixture 50/50 for making 6 lb of 50/50 mixture.


4 0
2 years ago
An ice cube is melting, and the lengths of its sides are decreasing at a rate of 0.8 millimeters per minute At what rate is the
julia-pushkina [17]

Answer:

The rate of decrease is: 43.2mm^3/min

Step-by-step explanation:

Given

l = 18mm

\frac{dl}{dt} = -0.8mm/min ---- We used minus because the rate is decreasing

Required

Rate of decrease when: l = 18mm

The volume of the cube is:

V = l^3

Differentiate

\frac{dV}{dl} = 3l^2

Make dV the subject

dV = 3l^2 \cdot dl

Divide both sides by dt

\frac{dV}{dt} = 3l^2 \cdot \frac{dl}{dt}

Given that: l = 18mm and \frac{dl}{dt} = -0.8mm/min

\frac{dV}{dt} = 3 * (18mm)^2 * (-0.8mm/min)

\frac{dV}{dt} = 3 * 18 *-0.8mm^3/min

\frac{dV}{dt} = -43.2mm^3/min

<em>Hence, the rate of decrease is: 43.2mm^3/min</em>

8 0
2 years ago
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