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GarryVolchara [31]
3 years ago
5

Question 1: Which equation shows p(x)=x^6−1 factored completely over the integers? (Hint: You will need to use more than one met

hod to complete this problem.)
a. p(x)=(x^3+1)(x^3−1)
b. p(x)=(x^2−1)(x^4+x^2+1)
c. p(x)=(x−1)(x^2+x+1)(x+1)(x^2−x+1)
d. p(x)=(x−1)(x+1)(x4+x^2+1)

Question 2: Which expression is the expanded form of p(x)=4(x−7)(2x^2+3)?

a. 32x^3−224x^2+48x−336
b. −48x^2+12x−84
c. 8x^3−56x^2+12x−84
d. 8x^3+56x^2−12x−84
Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

Question #1:  Option C, (x - 1)(x^2 + x + 1)(x + 1)(x^2 - x + 1)

Question #2:  Option C, 8x^3−56x^2+12x−84

Step-by-step explanation:

Question #1

<u>Step 1:  Factor</u>

p(x) = x^6 - 1

<em>p(x) = (x + 1)(x - 1)(x^2 + x + 1)(x^2 - x + 1)</em>

<em />

Answer:  Option C, (x - 1)(x^2 + x + 1)(x + 1)(x^2 - x + 1)

Question #2

<u>Step 1:  Expand</u>

p(x) = 4(x - 7)(2x^2 + 3)

p(x) = (4x - 28)(2x^2 + 3)

p(x) = 8x^3 + 12x - 56x^2 - 84

<em>p(x) = 8x^3 - 56x^2 + 12x - 84</em>

<em />

Answer:  Option C, 8x^3−56x^2+12x−84

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