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mamaluj [8]
3 years ago
12

elle wanted to order candy online. Company a is offering two and a half lbs. of chocolate for $32.50 while company b is offering

two and three fourths lbs. of the same chocolate for $35.00. Which company is offering the lowest price per pound?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

company B offers less per pound

Step-by-step explanation:

company A offers $13 per pound while company B offers $12.7 per pound

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Solve for x. week 13 test
Whitepunk [10]

Answer: x equals 174

Step-by-step explanation: This looks like a parallelogram and if it is then the side opposite 157 would also be 157 so u just had to add 17 to 157 and thats ur answer of 174.

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3 years ago
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Solve the problem below:<br><br>9+10=​
Elan Coil [88]

Answer:

19

Step-by-step explanation:

qwertyuiop[sdfghjkl;zxcvbnm,.

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2 years ago
a square has a side length of x. A rectangle has a length that is 4 inches longer than the square and a width that is 2 inches s
vodomira [7]

Answer:

Length of the rectangle is = 8 inches.

Step-by-step explanation:

Given :

Area of square = Area of the rectangle

According to the question:

Length of the square be 'x'.

Its area = (Side)*(Side) =x^2   ...equation (i)

Length of the rectangle = (x+4)

Width of the rectangle = (x-2)

Area of the rectangle =Length * Width

⇒(x+4)(x-2)=x^2-2x+4x-8

⇒x^2+2x-8          ...equation  (ii)

Equating both the equation as area of both the figure are equal.

⇒ x^2+2x-8=x^2

⇒ 2x-8=0     ...subtracting x^2 both sides

⇒ 2x=8           ...dividing both sides with 2

⇒ x=\frac{8}{2}=4 inches

Plugging the value of x=4 in the length of the rectangle.

We have,

⇒(x+4)=(4+4)=8

So the length of the rectangle = 8 inches.

4 0
3 years ago
What's the cube root of 81?
Alexxandr [17]

The cube root of 81 is 4.32674871092

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3 years ago
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This is finding exact values of sin theta/2 and tan theta/2. I’m really confused and now don’t have a clue on how to do this, pl
Lostsunrise [7]

First,

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

and given that 90° < <em>θ </em>< 180°, meaning <em>θ</em> lies in the second quadrant, we know that cos(<em>θ</em>) < 0. (We also then know the sign of sin(<em>θ</em>), but that won't be important.)

Dividing each part of the inequality by 2 tells us that 45° < <em>θ</em>/2 < 90°, so the half-angle falls in the first quadrant, which means both cos(<em>θ</em>/2) > 0 and sin(<em>θ</em>/2) > 0.

Now recall the half-angle identities,

cos²(<em>θ</em>/2) = (1 + cos(<em>θ</em>)) / 2

sin²(<em>θ</em>/2) = (1 - cos(<em>θ</em>)) / 2

and taking the positive square roots, we have

cos(<em>θ</em>/2) = √[(1 + cos(<em>θ</em>)) / 2]

sin(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / 2]

Then

tan(<em>θ</em>/2) = sin(<em>θ</em>/2) / cos(<em>θ</em>/2) = √[(1 - cos(<em>θ</em>)) / (1 + cos(<em>θ</em>))]

Notice how we don't need sin(<em>θ</em>) ?

Now, recall the Pythagorean identity:

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

Dividing both sides by cos²(<em>θ</em>) gives

1 + tan²(<em>θ</em>) = 1/cos²(<em>θ</em>)

We know cos(<em>θ</em>) is negative, so solve for cos²(<em>θ</em>) and take the negative square root.

cos²(<em>θ</em>) = 1/(1 + tan²(<em>θ</em>))

cos(<em>θ</em>) = - 1/√[1 + tan²(<em>θ</em>)]

Plug in tan(<em>θ</em>) = - 12/5 and solve for cos(<em>θ</em>) :

cos(<em>θ</em>) = - 1/√[1 + (-12/5)²] = - 5/13

Finally, solve for sin(<em>θ</em>/2) and tan(<em>θ</em>/2) :

sin(<em>θ</em>/2) = √[(1 - (- 5/13)) / 2] = 3/√(13)

tan(<em>θ</em>/2) = √[(1 - (- 5/13)) / (1 + (- 5/13))] = 3/2

3 0
2 years ago
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