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alex41 [277]
3 years ago
9

A bootle of sugar syrup soda had 3 3/5 grams of sugar in it. If Oliver drank 3 full bottles and 2/5 of a bottle, how many grams

of sugar did he drink?
Mathematics
1 answer:
Natali [406]3 years ago
5 0
The ACTUAL answer is 12.24. I got it wrong when I said 15.12.


Explanation: 3 3/5 turn it into an improper fraction = 18/5.



18/5 = 3.6 in decimal form x 3 full bottles= 10.8 sugar in three bottles.




3.6 in one bottle, finding 2/5 of that means 3.6 divided by 5 = 0.72 x 2 = 1.4



10.8 + 1.44 =12.24
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If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
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Find the sum of three consecutive odd integers where x is the greatest integer
myrzilka [38]
X + (x − 2) + (x − 4) = ? ;  In which
<span>
x + x </span>− 2 + x − 4 ; 

Combine the "like terms" ; 

  x + x + x = 3x ; 

  − 2 − 4  =  −6 ; 

So we have:  "3x  − 6" as the sum. ;
___________________________
The sum of three consecutive odd integers, in which "x" is the greatest integer;  is:  "3x − 6" .
_____________________________________________
Note:  The three consecutive odd integers, from least to greatest, are:

"(x − 4)" , "(x − 2)" , and "x" .

The sum is:  "(3x  − 6)<span>" .
</span>_____________________________________________
Note:  "(3x  − 6)" factors into:  " 3(x −2)" .

Note that:  " (x − 2) " is the second integer.
______________________________________________
So the sum total, which is:  "(3x  −  6)" ;  is 3 (three) times the value of the second integer; that is, "3 (x − 2)" .
______________________________________________
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