3 years ago

Find vertex and y- intercept and x-intercept in x^2 -2x-15

Mathematics

1 answer:

AfilCa [17]3 years ago

4 0

It would be (x-5)(x+3)

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Factor the quadratic equation below to reveal the solutions. X^2+4x-21=-9

a_sh-v [17]

Answer:

x = 3 and x = -7

Step-by-step explanation:

The given quadratic equation is $x^2+4x-21=0$ . We need to find the solution of this equation.

If the equation is in the form of $ax^2+bx+c=0$ , then its solutions are given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = 1, b = 4 and c = -21

Plugging all the values in the value of x, such that :

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a},\dfrac{-b- \sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-4+ \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)},\dfrac{-4- \sqrt{(4)^2-4\times 1\times (-21)} }{2(1)}\\\\x=3, -7$

So, the solutions of the quadratic equation are 3 and -7.

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Y=4x-13

that is the line

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3 years ago

NEED HELPPPPP LOL XDDDDD OH MY GODDD

DedPeter [7]

Answer:

yo w t f is thisssssss

Step-by-step explanation:

b c idek im so cluless rn im in 7th grade XD

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