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vova2212 [387]
3 years ago
13

Patty wants a triangle garden in her backyard for all of her vegetables. She

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

the hypothenuse is the largest side in the right triangle

we have 2 side, 7,8

in a right triangle, c^2= a^2+b^2

where c is the hypothenuse

c^2=49+64=113

c=sqrt113=aprox 10.6

so, the answer is no if it has to be exactly 10 ft the hypotenuse

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1. The sides of a triangle have lengths of 5, 8, and 6.(1/ 2). An angle bisector meets the side of length 6.(1/ 2). Find the len
Advocard [28]

Answer:

Step-by-step explanation:

i assume x+y=6(1/2)=\frac{13}{2}

\frac{5}{8}=\frac{x}{y}=\frac{x}{\frac{13}{2}-x}=\frac{2x}{13-2x}\\65-10x=16x \\26 x=65\\2x=5\\x=\frac{5}{2}\\y=\frac{13}{2}-\frac{5}{2}=\frac{8}{2}=4

6 0
3 years ago
In the figure, GK bisects FGH
bija089 [108]

Answer:

w = 7

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

104 = 2*(7w + 3) (substitution)

Divide both sides by 2

\frac{104}{2} = \frac{2*(7w + 3)}{2}

52 = 7w + 3

Subtract 3 from each side

52 - 3 = 7w + 3 - 3

49 = 7w

Divide both sides by 7

\frac{49}{7} = \frac{7w}{7}

7 = w

w = 7

8 0
3 years ago
Can someone help me with number 4?
Rashid [163]
The US: 300m World: 9b Most accurate: B

300m•20=6b population

B is the most accurate
4 0
3 years ago
F(x)= (x+2)^2 -1<br> Find x intercept <br> Find y intercept<br> Find vertex
Trava [24]
The x intercept occurs when y = 0.

0=(x+2)^2 - 1
1=(x+2)^2

Take the square root of both sides. Note that the sqrt of 1 is 1. Then solve for x.

1=x+2
-1=x

The x intercept is -1.

The y intercept occurs when x=0.

y=(0+2)^2 - 1
y=2^2 -1
y=4-1
y=3

The y intercept is 3.

Now, to find the vertex...

This parabola is currently in a format called the vertex form, which is:

f(x) = (x-h)^2 + k

where (h, k) is the vertex.

Therefore, the vertex is (-2, -1).
6 0
3 years ago
Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.
Rashid [163]

Answer:

The following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Step-by-step explanation:

Lets solve all the expressions to match the results.

  • 5\left(2t+1\right)+\left(-7t+28\right)

<em>Solving the expression</em>

5\left(2t+1\right)+\left(-7t+28\right)

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

5\left(2t+1\right)-7t+28

10t+5-7t+28

3t+33

Therefore, 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33

  • 3\left(3t-4\right)-\left(2t+10\right)

<em>Solving the expression</em>

3\left(3t-4\right)-\left(2t+10\right)

9t-12-\left(2t+10\right)

9t-12-2t-10

7t-22

Therefore, 3\left(3t-4\right)-\left(2t+10\right) = 7t-22

  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

<em>Solving the expression</em>

\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)

4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)

4t-\frac{8}{5}-3+\frac{4t}{3}

As

-3-\frac{8}{5}:\quad -\frac{23}{5}    and  \frac{4t}{3}+4t:\quad \frac{16t}{3}

So,

4t-\frac{8}{5}-3+\frac{4t}{3} will become \frac{16t}{3}-\frac{23}{5}

Therefore, \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}

  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

<em>Solving the expression</em>

\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

-\frac{9}{2}t+3+\frac{7}{4}t+33

\mathrm{Group\:like\:terms}

\frac{9}{2}t+\frac{7}{4}t+3+33

\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t

-\frac{11}{4}t+3+33

-\frac{11}{4}t+36

Therefore, \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Thus, the following pairs/results are matched:

  • 5\left(2t+1\right)+\left(-7t+28\right) = 3t+33
  • 3\left(3t-4\right)-\left(2t+10\right) = 7t-22
  • \left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right) = \frac{16t}{3}-\frac{23}{5}
  • \left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right) = -\frac{11}{4}t+36

Keywords: algebraic expression

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

5 0
3 years ago
Read 2 more answers
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