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2 years ago

The distance formula is d=r/t. how long will it take (in hours) to travel 100 miles at a rate of 22mph? Show all work.

Mathematics

1 answer:

Gala2k [10]2 years ago

3 0

divide the distance ( 100 miles) by the speed ( 22 mph) to get the time

100/22 = 4.545454 hours (Round to 4.5 hours ?)

if you need hours and minutes multiply 0.545454 by 60 to get the minutes

4 hours 32.7 ( round to 33) 4 hours and 33 minutes

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Help plz...........................

stich3 [128]

Answer:So its simple just forget about the letters add the numbers then place the letter and x

Step-by-step explanation: ( Always Parentheses first) Then i think you divide it by the outside number

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3 years ago

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The heat index I is a measure of how hot it feels when the relative humidity is H (as a percentage) and the actual air temperatu

PSYCHO15rus [73]

Answer:

a) $I(95,50) = 73.19$ degrees

b) $I_{T}(95,50) = -7.73$

Step-by-step explanation:

An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

a) Calculate I at (T ,H) = (95, 50).

$I(95,50) = 45.33 + 0.6845*(95) + 5.758*(50) - 0.00365*(95)^{2} - 0.1565*95*50 + 0.001*50*95^{2} = 73.19$ degrees

(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.

This is the partial derivative of I in function of T, that is $I_{T}(T,H)$ . So

$I(T,H) = 45.33 + 0.6845T + 5.758H - 0.00365T^{2} - 0.1565TH + 0.001HT^{2}$

$I_{T}(T,H) = 0.6845 - 2*0.00365T - 0.1565H + 2*0.001H$

$I_{T}(95,50) = 0.6845 - 2*0.00365*(95) - 0.1565*(50) + 2*0.001(50) = -7.73$

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3 years ago

Help pls !! how would I write this equation

aev [14]

2x = Twice your age

200 = Two hundred less

> -1 = more than negative

With the information given, your equation would be:

200-2x>-1

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3 years ago

1. A box of fruit has 12 plums and 15 bananas. The

sukhopar [10]

Answer:

12p x (15 x 25) I might not be correct :')

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2 years ago

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List the domain and range of the relation.<br> {(5,-5), (7,7), (0,-5), (7,1) (5,5)}

artcher [175]

Answer:

domain = (0,5,7)

range = (-5,1,5,7)

Step-by-step explanation:

domains are the x in (x,y) , and ranges are y in the (x,y) relations.

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3 years ago