All categories

3 years ago

The distance formula is d=r/t. how long will it take (in hours) to travel 100 miles at a rate of 22mph? Show all work.

Mathematics

1 answer:

Gala2k [10]3 years ago

3 0

divide the distance ( 100 miles) by the speed ( 22 mph) to get the time

100/22 = 4.545454 hours (Round to 4.5 hours ?)

if you need hours and minutes multiply 0.545454 by 60 to get the minutes

4 hours 32.7 ( round to 33) 4 hours and 33 minutes

You might be interested in

What is the solution set for this inequality? |3x+3|≤9 Graph the solution set on the number line.

soldi70 [24.7K]

Answer:

Step-by-step explanation:

because it's an absolute value inequality, there are two inequalities to solve

3x+3 ≤ 9 and 3x+3 ≥ -9, now we solve them separately

x ≤ 3 and x ≥ -4, which is -4 ≤ x ≤ 3

8 0

3 years ago

Read 2 more answers

The perimeter of a sand volleyball court is 52 meters. It is 8 meters wide. How long is it?

kolezko [41]

Answer:

18 meters if my mental math is right.

6 0

3 years ago

Solve the following problem:

emmasim [6.3K]

Answer:

24 ^people because if one pizza is for 3 personnes its 8x3=24

Step-by-step explanation:

3 0

3 years ago

Which expression is equivalent to 4+ [4 x (5-2)] + 2?

zimovet [89]

Answer:

Step-by-step explanation:

which expression is equivalent to 4+ [4 x (5-2)] + 2?

A 4 + 12+2

B 4 + 18 + 2

C 8x3 + 2

D 8 x 5 - 1

4+ [4 x (5-2)] + 2 = 18

A 4 + 12+2 = 18

B 4 + 18 + 2 = 24

C 8x3 + 2 = 26

D 8 x 5 - 1 = 39

check

4 + [4 x (5-2)]+ 2 = 4 + 12 + 2

18 = 18

the answer is good

6 0

2 years ago

The boy wants to build rectangular beetle cages to study beetle behavior. He wants all the sides on the base of his cages to be

kap26 [50]

Answer:

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

Step-by-step explanation:

<u><em>The complete question is</em></u>

A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?

we know that

The number 576 decompose in prime factors is the same that write

$576=(2^6)(3^2)$

To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)

3x3=9cm 2x2x2x2x2x2= 64cm ----> is not a combination (one side is not greater than 10)

3x3x2= 18cm 2x2x2x2x2= 32cm

3x3x2x2= 36cm 2x2x2x2= 16cm

3x2x2= 12cm 3x2x2x2x2= 48cm

3x2x2x2= 24cm 3x2x2x2= 24cm

therefore

32 cm by 18 cm

16 cm by 36 cm,

48 cm by 12 cm

24 cm by 24 cm

3 0

3 years ago