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3 years ago

13

Evaluate 80 - 5( 2 + 7 ) + 15

2 answers:

Maru [420]3 years ago

5 0

Answer:

50

Step-by-step explanation:

im smart

xxMikexx [17]3 years ago

3 0

Answer:

80-5(2+7)+15

=80-5(9)+15

=50-45+15

=5+15

=25

Let me know if this helps!

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Describe how you can use compatible numbers to estimate 17 x 27

Varvara68 [4.7K]

Answer:

600

Step-by-step explanation:

Well, the closest number for 17 is 20, and for 27 is 30.

When we multiply those two numbers :

20*30=600

We got 600

5 0

3 years ago

The probability that a certain hockey team will win any given game is 0.3773 based on their 13 year win history of 389 wins out

notsponge [240]

Answer:

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the teams wins, or they do not win. The probability of the team winning a game is independent of any other game, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3773.

This means that $p = 0.3773$

Their schedule for November contains 12 games.

This means that $n = 12$

Find the probability that the hockey team wins at least 3 games in November.

This is:

$P(X \geq 3) = 1 - P(X < 3)$

In which:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.3773)^{0}.(0.6227)^{12} = 0.0034$

$P(X = 1) = C_{12,1}.(0.3773)^{1}.(0.6227)^{11} = 0.0247$

$P(X = 2) = C_{12,2}.(0.3773)^{2}.(0.6227)^{10} = 0.0824$

Then

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0034 + 0.0247 + 0.0824 = 0.1105$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.1105 = 0.8895$

0.8895 = 88.95% probability that the hockey team wins at least 3 games in November.

3 0

3 years ago

Your help would be appreciated

Schach [20]

Answer:

I think its the 1st one, but I'm not sure

8 0

3 years ago

Equivalent of (17×4)−35

Thepotemich [5.8K]

17 times 4, you get 68. 68 minus 35, your answer is 33
17*4=68
68-35=33

3 0

3 years ago

Range, mode, MAD, median IQR, mean

Jlenok [28]

Answer:

range=8, mode=1 Median=3 mean=4

Step-by-step explanation:

range= subtract largest from smallest

mode= most frequent

median= middle in an ordered data set

Mean= add them all up and divide by how many you addded up

6 0

3 years ago

Read 2 more answers