The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is 
<u>Solution:</u>
Given, two points are (-6, 6) and (-3, -9)
We have to find the midpoint of the segment formed by the given points.
The midpoint of a segment formed by
is given by:


Plugging in the values in formula, we get,

Hence, the midpoint of the segment is 
Answer:
The answer is 5/8
Step-by-step explanation:
Step 1 : Convert both fractions so they have the same denominator (bottom number in the fraction.)
1/4 = 2/8
So now were dealing with :
2/8 + 3/8 = ?
Step 2 : Add the numerators together to get the numerator for our answer.
2 + 3 = 5
When adding two fractions with the same denominator the denominator stays the same, so our answer is 5/8.
Hope this helps, please mark brainliest. :) Have a nice day.
The length of rope(consist of 3 pieces)=9*2=18m
One piece=18/3=6m
Pls mark me as the Brainliest as I really need it!
Answer:
- 15
Step-by-step explanation:

Let n = required random sample size.
Assume that the population standard deviation is known as σ.
Let m = sample mean.
At the 95% confidence level, the expected range is
(m - k(σ/√n), m + k(σ/√n))
where k = 1.96.
Therefore the error margin is 1.96(σ/√n).
Because the error margin is specified as 3% or 0.03, therefore
(1.96σ)/√n = 0.03
√n = (1.96σ)/0.03
n = 128.05σ²
This means that the sample size is about 128 times the population variance.
Answer:
Smallest sample size = 128.05σ², where σ = population standard deviation.