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Sedbober [7]
3 years ago
14

What is ​ BC ​? ? ah

Mathematics
2 answers:
aniked [119]3 years ago
8 0
The little marks on the angles show that angle B equals Angle C, so the opposite sides AB and AC are also equal.
8x-4=5x+11
3x=15
x=5
BC=4x-2=4*5-2=18
bija089 [108]3 years ago
5 0
Before christ duh (BC)

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How do you find the arc length in a circle given any angle?
Nataly_w [17]

You find the circumference and multiply it by the central angle. If the central angle is in degrees, you divide that by 360. If the central angle is in radians, you divide by 2pi.

8 0
2 years ago
How do you add integers with the same sign? <br><br><br><br>PLEASE I NEED IT NOW AND THANK YOU
dedylja [7]
When you add integers, you keep the sign on the sum.

For example:
-9 + -9 = -18 (kept the sign)
9 + 9 = 18 (kept the "sign")
3 0
2 years ago
Help and ill give brainliest
jenyasd209 [6]

Answer:

10

Step-by-step explanation:

The band gets 1/2 of the total amount of water. The total amount collected is twice as much as what the band gets. Multiply 5 by 2 to get 10

Brainliest Please

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3 0
2 years ago
Use cramers Rule to solve the following system:
Jet001 [13]

Answer:

The solution to the system is x=1,y=-2 and z=-5

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

x= \frac{D_x}{D}, y= \frac{D_y}{D} and z= \frac{D_z}{D} where D_x, D_y and D_z are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. D is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]

Then each of the previous determinants are given by:

D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199 Notice how the x-column has been substituted with the answer-column one.

D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398 Notice how the y-column has been substituted with the answer-column one.

D_z = \left|\begin{array}{ccc}5&-3&6\\0&2&11\\7&10&-13\end{array}\right|=-995

Then, substituting the values:

x= \frac{D_x}{D}=\frac{199}{199}\\ x=1

x= \frac{D_y}{D}=\frac{-398}{199}\\ y=-2

x= \frac{D_z}{D}=\frac{-995}{199}\\ x=-5

3 0
2 years ago
Please help asap!!!!
AleksandrR [38]

Answer:

justin biberis black

Step-by-step explanation:

8 0
2 years ago
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