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Alla [95]
3 years ago
6

A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm.

Mathematics
2 answers:
ddd [48]3 years ago
7 0
Sin 23° = Opposite/Hypotenuse = b / c
0.39 = b / 30
b = 0.39 · 30
b = 11.722 cm
Area of a triangle:
A = 1/2 b h
A = 1/2 · 11.722 · 27.6
A  ≈ 161.7 cm²
Answer:
B ) 161.7 cm²
Mariana [72]3 years ago
4 0

Answer:

The Answer is B.161.7 m2

Step-by-step explanation:

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Please help I’ll mark you as brainliest if correct!
Darya [45]

Answer:

A is 4

Step-by-step explanation:

A _ 8 _ _ _ _ _ _ _ _ 8 _ 6

A _ 8 _ _ _ _ _ _ _ _ 8 4 6

A _ 8 _ _ _ _ _ _ _ 6 8 4 6

A _ 8 _ _ _ _ _ _ 4 6 8 4 6

A _ 8 _ _ _ _ _ 8 4 6 8 4 6

A _ 8 _ _ _ _ 6 8 4 6 8 4 6

A _ 8 _ _ _ 4 6 8 4 6 8 4 6

A _ 8 _ _ 8 4 6 8 4 6 8 4 6

A _ 8 _ 6 8 4 6 8 4 6 8 4 6

A _ 8 4 6 8 4 6 8 4 6 8 4 6

A 6 8 4 6 8 4 6 8 4 6 8 4 6

4 6 8 4 6 8 4 6 8 4 6 8 4 6

A is 4

Hope this helps!

4 0
3 years ago
Read 2 more answers
13. What is the absolute value of I -32 I?
Temka [501]

Answer:

32

Step-by-step explanation:

7 0
3 years ago
PLEASEEE HELPPP<br><br> Solve for x:
m_a_m_a [10]

Second option, just do Pemdas backwards.

5 0
3 years ago
Rewrite the equation 2x+8y=16 in slope-intercept form
Shkiper50 [21]
The goal is to solve for y. Start by subtracting 2x from both sides. This gives you 8y=-2x+16. Now just divide both sides by 8, which gives you y=-2/8x+16/8. Finally, simplify this to y=-1/4x+2.
7 0
3 years ago
Literally noone answers my questions please help
prohojiy [21]

Answers:

  • slower train = 139 km per hour
  • faster train = 159 km per hour

=================================================

Explanation:

x = rate of the slower train

x+20 = rate of the faster train

rates are in km per hour, abbreviated as kph

The train traveling at x kph will travel 5x km after 5 hours.

Use this formula

distance = rate*time

Using that same formula, the faster train travels 5(x+20) = 5x+100 kilometers in 5 hours.

The two distances must add to 1490 if we want the trains to pass by each other. Assume that the trains are traveling on parallel side-by-side tracks.

--------------------------

So,

(slower train distance) + (faster train distance) = 1490

(5x) + (5x+100) = 1490

10x+100 = 1490

10x = 1490-100

10x = 1390

x = 1390/10

x = 139

The slower train moves at a rate of 139 km per hour.

x+20 = 139+20 = 159

The faster train moves at a speed of 159 km per hour.

--------------------------

Check:

The slower train travels 139 kph and travels for 5 hours, so it covers a distance of 139*5 = 695 km

The faster train has a speed of 159 kph and travels for 5 hours, so it covers 159*5 = 795 km

Total distance = 695+795 = 1490

The answers are confirmed.

7 0
2 years ago
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