$LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS$

Hint: 1 - Cos² A = Sin² A

4 0

3 years ago

28 Marks

OLga [1]

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

8 0

3 years ago

A local company manufactures netbook computers. Their profit function is given by this equation: y equal minus x to the power of

Westkost [7]

Answer by BlueSky06

The equation described above can also be written as, y = -x² + 100x + 4000To get the number of notebooks that will give them the maximum profit, we derive the equation and equate to zero. dy/dx = -2x + 100 = 0The value of x from the equation is 50. Then, we substitute 50 to the original equation to get the profit. y = -(50^2) + 100(50) + 4000 = 6500Thus, the maximum profit that the company makes is $6,500/day.
Read more on Brainly.com - brainly.com/question/3586459#readmore

3 0

3 years ago

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