Answer:
27
12
3
0
3
12
27
Step-by-step explanation:
y=3x^2
JUST PLUG IN X
Answer:
Option (3)
Step-by-step explanation:
Since, flowerbed is in the shape of a right triangle,
By applying Pythagoras theorem in the given right triangle,
(Hypotenuse)² = (leg 1)² + (leg 2)²
(Hypotenuse)² = (12)² + (12)²
(Hypotenuse)² = 144 + 144
Hypotenuse = √288
Hypotenuse = 16.97
≈ 17 ft
Perimeter of the triangle = Sum of the measures of three sides of the triangle
= 12 + 12 + 17
= 41 ft
Therefore, Option (3) will be the correct option.
Answer:
Perimeter of i - 22CM
Area of i - 13CM^2
Perimeter of ii -38CM
Area of ii -66CM^2
Perimeter of iii -30CM
Area of iii- 42CM^2
Perimeter of iv - 50CM
Area of iv- 126CM^2
Step-by-step explanation:
SHAPE I:
PERIMETER = S + S + S + S + S +S
= 7 + 1 + 5 +3 +4 +2
= 22CM
AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2
Total = 8 + 5 = 13cm^2
SHAPE II:
PERIMETER = S + S + S + S + S +S
= 4 + 4 +5 + 6 + 9 + 10
= 38 CM
AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2
Total = 50+16 =66 cm^2
SHAPE III:
PERIMETER = S + S + S + S + S +S
= 9 + 2 + 3 + 4 + 6 + 6
= 30CM
AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2
Total = 36 + 6 =42 cm^2
SHAPE IV:
PERIMETER = S + S + S + S + S +S
= 9 + 10 + 4 + 6 + 6 + 15
= 50 CM
AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2
Total = 90 + 36 = 126cm^2
HOPE THIS HELPED
Answer:
Step-by-step explanation:
<, > - open circle
≤, ≥ - closed circle
<, ≤ - draw the line to the left
>, ≥ - draw the line to the right
Hello!
This question is about which values you are changing when you are transforming an equation.
Let's go through the parent function for an absolute value equation and its various transformations.
Since we are only looking at horizontal and vertical transformations, we only need to worry about the c and d values.
The c value of a function determines a function's horizontal position, and the d value of a function determines a function's vertical position.
One thing to note here is that the c value is being subtracted from the x value, meaning that if the function is being transformed to the right, you would actually be subtracting that value, while the d value behaves like a normal value, if it is being added, the function is transformed up, and vice versa.
Now that we know this, let's write each expression.
a)
b)
c)
d)
Hope this helps!